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Degger [83]
2 years ago
14

Copy the problems on to your paper. Use your notes as reference.

Mathematics
1 answer:
____ [38]2 years ago
6 0

Answer:

1. x⁴³/³⁵

2. 1/x⁶

3. x⁴/2

Step-by-step explanation:

1. ⁷√x³. ⁵√x⁴

The above expression can be simplified as follow:

Recall:

ᵐ√aⁿ = aⁿ/ᵐ

⁷√x³ × ⁵√x⁴ = x³/⁷ × x⁴/⁵

Recall:

aⁿ × aᵐ = aⁿ⁺ᵐ

x³/⁷ × x⁴/⁵ = x⁽³/⁷ ⁺ ⁴/⁵⁾ = x⁴³/³⁵

Therefore,

⁷√x³. ⁵√x⁴ = x⁴³/³⁵

2. x¯³ / x⁵x¯²

The above expression can be simplified as follow:

Recall:

aⁿ × aᵐ = aⁿ⁺ᵐ

x⁵x¯² = x⁵ ⁺ ⁽¯²⁾ = x⁵ ¯ ² = x³

Thus,

x¯³ / x⁵x¯² = x¯³ / x³

Recall:

aⁿ / aᵐ = aⁿ ¯ ᵐ

x¯³ / x³ = x¯³ ¯ ³ = x¯⁶

Recall

a¯ⁿ = 1/aⁿ

x¯⁶ = 1/x⁶

Therefore,

x¯³ / x⁵x¯² = 1/x⁶

3. 5(x⁴)³ / 10x⁸

The above expression can be simplified as follow:

Recall:

(aⁿ)ᵐ = aⁿ×ᵐ

5(x⁴)³ / 10x⁸ = 5x¹² / 10x⁸

Recall:

aⁿ / aᵐ = aⁿ ¯ ᵐ

5x¹² / 10x⁸ = (5/10)x¹² ¯ ⁸ = 1/2 x⁴ = x⁴/2

Therefore,

5(x⁴)³ / 10x⁸ = x⁴/2

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Answer:

x = 17.2

Step-by-step explanation:

since they are supplementary, when you add then together they equal 180

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Combine like terms

10x + 8 = 180

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hope this helps :)

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Step-by-step explanation:

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Anika [276]
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3 years ago
(10000*C)/1.05+(10000*C)/1.05^2…..(10000*C)/1.05^13=100<br> Find C?
rosijanka [135]

9514 1404 393

Answer:

  C ≈ 0.00106455765168

Step-by-step explanation:

This is the sum of 13 terms of the geometric series that has 10000C/1.05 as the first term and a common ratio of 1/1.05. The sum S is given by ...

  S = a1(1 -r^n)/(1 -r) . . . . a1 is the first term, r is the common ratio

Using the known values, we have ...

  100 = (10000C/1.05)(1 -1.05^-13)/(1 -1/1.05))

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  C ≈ 0.00106455765168

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3 years ago
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