Answer:
please read the answer below
Explanation:
To find the electric field you can consider the Gaussian law for a cylindrical surface inside the slab.
![\int E dA=EA_{G}=\frac{Q_{int}}{\epsilon_o}](https://tex.z-dn.net/?f=%5Cint%20E%20dA%3DEA_%7BG%7D%3D%5Cfrac%7BQ_%7Bint%7D%7D%7B%5Cepsilon_o%7D)
![Q_{int}=\rho V_{G}](https://tex.z-dn.net/?f=Q_%7Bint%7D%3D%5Crho%20V_%7BG%7D)
where Qint is the charge inside the Gaussian surface, AG is the area of the surface and rho is the charge density of the slab.
By using the formula for the volume of a cylinder you obtain:
![V_{G}=\pi r^2h](https://tex.z-dn.net/?f=V_%7BG%7D%3D%5Cpi%20r%5E2h)
where h is the height. If you assume that the slab is in the interval (-zo<z<z0) you can write VG:
![V_{G}=\pi r^2 z](https://tex.z-dn.net/?f=V_%7BG%7D%3D%5Cpi%20r%5E2%20z)
Finally, by replacing in the expression for E you get:
![E=\frac{Q_{int}}{\epsilon_o A_G}=\frac{Q_{int}}{\epsilon_o \pi r^2}\frac{z}{z}=\frac{\rho z}{\epsilon_o}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BQ_%7Bint%7D%7D%7B%5Cepsilon_o%20A_G%7D%3D%5Cfrac%7BQ_%7Bint%7D%7D%7B%5Cepsilon_o%20%5Cpi%20r%5E2%7D%5Cfrac%7Bz%7D%7Bz%7D%3D%5Cfrac%7B%5Crho%20z%7D%7B%5Cepsilon_o%7D)
![E=\rho z/\epsilon_o](https://tex.z-dn.net/?f=E%3D%5Crho%20z%2F%5Cepsilon_o)
hence, for z>0 you obtain E=pz/eo > 0
for z<0 -> E=pz/eo < 0
Answer:
Length of the string, l = 0.486 meters
Explanation:
It is given that,
Mass of the string, ![m=2.4\times 10^{-3}\ kg](https://tex.z-dn.net/?f=m%3D2.4%5Ctimes%2010%5E%7B-3%7D%5C%20kg)
Tension in the string, T = 120 N
Frequency of transverse wave, f = 260 Hz
Wavelength of the wave, ![\lambda=0.6\ m](https://tex.z-dn.net/?f=%5Clambda%3D0.6%5C%20m)
The speed of a transverse wave (v) is given by :
........(1)
<em>Where,</em>
![\mu=\dfrac{m}{l}](https://tex.z-dn.net/?f=%5Cmu%3D%5Cdfrac%7Bm%7D%7Bl%7D)
Also, speed of a wave,
.........(2)
From equation (1) and (2) :
![l=\dfrac{f^2\lambda^2m}{T}](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7Bf%5E2%5Clambda%5E2m%7D%7BT%7D)
![l=\dfrac{(260\ Hz)^2\times (0.6\ m)^2\times 2.4\times 10^{-3}\ kg}{120\ N}](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7B%28260%5C%20Hz%29%5E2%5Ctimes%20%280.6%5C%20m%29%5E2%5Ctimes%202.4%5Ctimes%2010%5E%7B-3%7D%5C%20kg%7D%7B120%5C%20N%7D)
l = 0.486 m
So, the length of the string is 0.486 meters. Hence, this is the required solution.
Answer:
The balanced equations are as follows:
✅ FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl
✅ CH₄ + O₂ ➡ CO₂ + 2H₂O
✅ 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂
✅ PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄
Explanation:
In the equation, FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl, Charlie will adjust the number of atoms in NH₄OH in order for NH₄, Cl and OH to balance in the product side. 3 was placed in front of NH₄OH and NH₄Cl in order the balance it.
In the equation, CH₄ + O₂ ➡ CO₂ + 2H₂O, Charlie will adjust the number of atoms in H₂O. 2 was placed in front of H₂O in order to balance the atoms in the reactant and product sides.
In the equation, 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂, Charlie will adjust the number of atoms in the reactant side in order for the product side to be balanced.
In the equation, PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄, Charlie will adjust the number of atoms in H₂O and HCl for the equation to be balanced. 4 and 5 were placed in front of H₂O and HCl respectively in order for the equation to be balanced.
In chemical equations, it is required that the number of atoms of each element found in the reactants must be equal to the number of atoms of each element found in the products. This makes the chemical equation balanced.
If a baseball dropped from the roof of a tall building takes 3.1 seconds to hit the ground, the height of the building would be 47.1 m.
According to Newton's second law of motion,
![s=ut+\frac{1}{2}at^{2}](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E%7B2%7D)
Where, s is the distance covered by the body, u is its initial velocity, t is the time taken by the body, and a is the acceleration of the body.
Here, the distance covered will be equal to the height of the building.
Since the ball was dropped, its initial velocity will be zero.
Also, the acceleration of the ball is the acceleration due to gravity,
.
Substituting the values,
![h=0+\frac{1}{2} gt^{2}](https://tex.z-dn.net/?f=h%3D0%2B%5Cfrac%7B1%7D%7B2%7D%20gt%5E%7B2%7D)
![h=\frac{1}{2} \times9.8\times3.1^{2}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes9.8%5Ctimes3.1%5E%7B2%7D)
![h=47.1m](https://tex.z-dn.net/?f=h%3D47.1m)
Therefore, the height of the building would be 47.1 m.
Learn more about Newton,s laws of motion here:
brainly.com/question/18730057
#SPJ1
Insurance would be a example of benefits because you don’t receive insurance like you would salary, salary is a base thing you receive when you get a job while insurance you only get as a benefit with certain jobs