A 45-45 90 triangle has two lengths that are equal, and the hypotenuse is √2 times those lengths.
Therefore:
Let x = the length of a leg (doesn't matter which one, they are equal)
√2 * x = 24 Divide both sides by √2
x = 24 / √2
To get the radical out of the denominator, multiply the right side by √2/√2
x = 24√2 / 2
x = 12√2 Answer is B
What Question are you stuck on??
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
The answer is d 8x^2 - 10
Answer:
7
Step-by-step explanation:
The left hand limit is when we approach zero from left. We use the function on this domain in finding the limit.
The right hand limit is
Since the left hand limit equals the right hand limit;
