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Rufina [12.5K]
2 years ago
15

How do i find the slope of a line??

Mathematics
2 answers:
sesenic [268]2 years ago
6 0

Answer:

Theres a equation your teacher gave you i cant remember right now but i thinks its yx+b

Step-by-step explanation:

denis-greek [22]2 years ago
4 0

Answer:

find 2 points from a line, then use the slope formula y2-y1

                                                                                       x2-x1

Step-by-step explanation:

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verb tense refers to when the action and a sentence takes place - whether it happened in the past, is happening in the present, or what is happening in the future.

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I need help on this if you know all the answers that would be great but if not I understand I am just struggling
tatyana61 [14]

Answer:

1. 8x+9

2. 3x + 11

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6 0
2 years ago
Read 2 more answers
Markus is finding that it takes too long to track down all of the groceries he needs to buy from a given store. GroceryGrabbr to
swat32

Answer:

A. The grocery list the user input

Step-by-step explanation:

4 0
3 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
2 years ago
Find two matrices A and B such that 2A-3B= [5 0
amm1812

The easy answer: If, say, B is the zero matrix, i.e.

B=\begin{bmatrix}0&0\\0&0\end{bmatrix}

then

2A=\begin{bmatrix}5&0\\-1&2\end{bmatrix}\implies A=\begin{bmatrix}\dfrac52&0\\\\-\dfrac12&1\end{bmatrix}

3 0
3 years ago
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