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PSYCHO15rus [73]
3 years ago
10

The half-life of a radioactive kind of radium is 11 days. If you start with 72 grams of it, how

Mathematics
1 answer:
NISA [10]3 years ago
4 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Radioactive decay.

N(t) = 72(1/2)^22/11

==> N(t) = 72 (1/2)^2

==> N(t) = 72/4

==> N(t) = 18 grams.

So the remaining would be 18 grams.

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The length of a rectangle is 5 m less than twice the width, and the area of the rectangle is 52 m^2. Find the dimensions of the
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length is 8m

Width is 6.5m

<u>Explanation:</u>

Let, width = b

So, length = 2b-5

area = 52m^{2}

We know,

area of rectangle = length X width

So, 52m^{2} = (2b-5) X b

On solving the above equation, we get

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3 years ago
I cant figure this out its x+1 &gt; 8 then<br> x= __. its inequalities math thank you
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3 years ago
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The U.S. Bureau of Labor Statistics reports that of persons who usually work full-time, the average number of hours worked per w
alukav5142 [94]

Answer:

The standard deviation of number of hours worked per week for these workers is 3.91.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem we have that:

The average number of hours worked per week is 43.4, so \mu = 43.4.

Suppose 12% of these workers work more than 48 hours. Based on this percentage, what is the standard deviation of number of hours worked per week for these workers.

This means that the Z score of X = 48 has a pvalue of 0.88. This is Z between 1.17 and 1.18. So we use Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{48 - 43.4}{\sigma}

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\sigma = \frac{4.6}{1.175}

\sigma = 3.91

The standard deviation of number of hours worked per week for these workers is 3.91.

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3 years ago
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3 years ago
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If 1/2 is the fraction representing the ratio of corresponding sides of two similar
Lynna [10]

Answer:

1/4

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