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Dmitry [639]
3 years ago
6

Using the given information, match the transformed equation from a parent function of

2" id="TexFormula1" title="y=x^2" alt="y=x^2" align="absmiddle" class="latex-formula"> or y=x^3
Question and choices below:

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Step-by-step explanation:

The general form for a quadratic or cubic equation is:

y = a (x − h)ⁿ + k

If |a| is between 0 and 1, it's a vertical shrink.  If |a| is greater than 1, it's a vertical stretch.  If a is negative, there's a reflection over the x-axis.

h is the horizontal translation.  If h is positive, there's a translation to the right.  If h is negative, there's a translation to the left.  (Notice the expression in the parentheses is x − h, not x + h, so if it helps, rewrite the equation.)

k is the vertical translation.  If k is positive, there's a translation up.  If k is negative, there's a translation down.

f(x) = (x + 1)³ − 7

f(x) = 1 (x − -1)³ + -7

a = 1, h = -1, k = -7

This is y = x³ translated 1 unit to the left and 7 units down.

g(x) = -½ (x − 2)³

g(x) = -½ (x − 2)³ + 0

a = -½, h = 2, k = 0

This is y = x³ reflected over the x-axis, vertical shrink of ½, and translated 2 units to the right.

y = -(x − 4)³ − 2

y = -1 (x − 4)³ + -2

a = -1, h = 4, k = -2

This is y³ reflected over the x-axis, translated 4 units right and 2 units down.

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The fourth option with x values of -3,-2,4 and 7 is a function of x.

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This is due to it having only one of each x value.

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Step-by-step explanation:


3 0
3 years ago
The length of a photograph is 3cm less than twice the width. The area is 54cm². Find the dimentions of the photograph.
AnnyKZ [126]
L=2w-3 

w(2w-3)=54

2w²- 3w-54=0

A= 2 , B= -3, C= -54

sub values into quadratic formula
 i attached picture of formula

Final answer:  you will be given 2 answers 6 and -4.5. -4.5 is rejected since a negative value cannot represent length because that just doesn't make sense.

w=6

Check:
L=2w-3
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=9
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Therefore the dimensions of the photograph are 6 cm by 9 cm



3 0
3 years ago
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Fill in the missing numbers along the sides of the triangle so that it contains each of the numbers from 4 through 12 exactly on
elixir [45]

Answer:  A B == 9 + 11   CD == 5 +7  E F == 6 + 10

Step-by-step explanation:

(This reminds me of a "formula" I developed a few years ago when I was photographing formal groups, and had to figyre out how many people to put in each row, and the rows had to be different lengths)  Anyway--

Get the sum of the numbers at the angles, subtract that number from 32, and that's the amount needed for the row.

Once I have that number, divide by 2 and split as "n + 1 and n-1

AB side:  angles given: 8 +4=12 , 32-12 =20  20/2 = 10;  10+1 =11  10-1=9

CD side: angles given:  8 + 12 =20, 32-20=12; 12/2 =6  6+1 =7 6-1 =5

EF side: angles given:  4 + 12 =16 32-16=16  My formula would have yielded 7+9, but those numbers were already used. Conveniently, 10 + 6 are left over.   Same principle, but + or - 2.

Thanks for the opportunity to work in this!

It is a fun way for me to end my participation in Brainly for a while. My school year is over!

Good Luck, Stay Safe!

8 0
3 years ago
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Answer:

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