$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago

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Anarel [89]

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7 0

3 years ago

Translate the sentence into an equation. Seven times the sum of a number and 4 is equal to 9. Use the variable b for the unknown

zzz [600]

Answer:

7 ( b + 4 ) = 9

Step-by-step explanation:

Let the number be = b

It is given that the :

The number is added to 4.

And the value is equal to 9 when it is 7 times the sum of the number, b and 4.

Thus according to the question, the sentence can be translated in equation form as :

7 ( b + 4 ) = 9

Thus in other word, we can say that the addition of (b + 4) when it is multiplied for 7 times, we get the result as 9.

4 0

2 years ago