<u>Answer:</u>
32 units
<u>Step-by-step explanation:</u>
We have a quadrilateral ABCD and we are given the following coordinates for these vertices:
A (-11,-6)
B (-3,0)
C (1,0)
D (1,-6)
AB =
= 10 units
BC =
= 4 units
CD =
= 6 units
AD =
= 12 units
Perimeter of ABCD =
= 32 units
Answer:
this cant be simplified unless you have an integer in place of "i"
Answer:
15
Step-by-step explanation:
5+20+15+18+20+19+12+16+10+15=150/10=15
Answer: 
Step-by-step explanation:
Let x be the equal sides of the triangle .
The , the third side would be x+113 cm.
The perimeter is the sum of all sides of a triangle.
So , The perimeter of triangle would be x+x+(x+113)= 3x+113 --------(1)
Since , it is given that the perimeter of triangle is 525. -----(2)
So from (1) and (2) , we have

Then, third side = 
Hence , the sides of a triangle are:
Answer:
V = 10 x 9 x (1/3)
V = 30 in³
Step-by-step explanation: