3 years ago

Find the imaginary solutions to the following quadratic function:

Mathematics

1 answer:

Temka [501]3 years ago

8 0

Answer:

the solutions are these

Step-by-step explanation:

$\frac{3}{14} + \frac{ \sqrt{159} }{14} i \: and \\ \: \frac{3}{14} - \frac{ \sqrt{159} }{14} i$

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Michelle and Natasha each had to repair their new iPhones. The initial cost of each repair is $ 100. Michelle and Natasha each h

worty [1.4K]

Answer:Michelle

And 50

Step-by-step explanation:

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3 years ago

For the data set shown in the scatterplot, what is the BEST approximation of the y-intercept for the line of best fit? A) 0 B) 5

Angelina_Jolie [31]

Answer:

C) 125

Step-by-step explanation:

If you add a line of best fit, its extension is likely to intersect the y-axis between 200 and 100 but closer to 100.

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2 years ago

If the ratio of the triangular pyramids' surface areas is 4:9, what is F?

VladimirAG [237]

Answer:

The answer to your question is f = 10.35 in

Step-by-step explanation:

Data

Proportion = 4:9

height 1 = 4.6 in

height 2 = f

Process

1.- Write the proportion

$\frac{4}{4.5} = \frac{9}{f}$

2.- Solve for f

$f(\frac{4}{4.6}) = f(\frac{9}{f})$

$f(\frac{4}{4.6}) = 9$

$4.6\frac{4f}{4.6} = 9(4.6)$

4f = 41.4

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3 years ago

The function sequalsf(t) gives the position of a body moving on a coordinate line, with s in meters and t in seconds. Find the

tia_tia [17]

Answer:

Δs=10m

$v_a_v=$ 5m/s

Step-by-step explanation:

s=t²+3t +5,0<=t<=2

Let f(t)=s=t²+3t +5

The displacement of the body over the time interval from 0 to 2 is

Δs=f(2)-f(0)

Δs=(2²+3(2) +5) - (0²+3(0) +5)

Δs=10m

The average velocity of the body over the time interval from 0 to 2 is

$v_a_v=$ displacement / travel time =Δs/Δt

=10 / 2

=5m/s

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3 years ago