Answer:
-6,0
Step-by-step explanation:
<em>Question:</em>
The area of the kite is 48 cm². What are the lengths of the diagonals PR and QS?
________
<em>Solution:</em>
You can split the kite into two isosceles triangles: PSR and PQR.
Assume that both diagonals intersect each other at the point O.
• Area of the triangle PSR:
m(PR) · m(OS)
A₁ = ————————
2
(x + x) · x
A₁ = ——————
2
2x · x
A₁ = ————
2
A₁ = x² (i)
• Area of the triangle PQR:
m(PR) · m(PQ)
A₂ = ————————
2
(x + x) · 2x
A₂ = ——————
2
2x · 2x
A₂ = ————
2
4x²
A₂ = ———
2
A₂ = 2x² (ii)
So the total area of the kite is
A = A₁ + A₂ = 48
Then,
x² + 2x² = 48
3x² = 48
48
x² = ———
3
x² = 16
x = √16
x = 4 cm
• Length of the diagonal PR:
m(PR) = x + x
m(PR) = 2x
m(PR) = 2 · 4
m(PR) = 8 cm
<span>• </span>Length of the diagonal SQ:
m(SQ) = x + 2x
m(SQ) = 3x
m(SQ) = 3 · 4
m(SQ) = 12 cm
I hope this helps. =)
Tags: <em>polygon area triangle plane geometry</em>
Answer:
3z
2
Step-by-step explanation:
Step 1
Given; If Body temperatures of healthy adults have a bell-shaped distribution with a mean of 98.20°F and a standard deviation of 0.93°F.
Using the empirical rule, what is the approximate percentage of healthy adults with body temperatures between 96.34°F and 100.06°F?
Step 2
![P(96.34The empirical rule states that 95% of the data fall within two standard deviations of the mean. Thus, 95% of healthy individuals have body temperatures between 96.34F and 100.06F.Answer;[tex]95\text{\%}](https://tex.z-dn.net/?f=P%2896.34The%20empirical%20rule%20states%20that%2095%25%20of%20the%20data%20fall%20within%20two%20standard%20deviations%20of%20the%20mean.%20Thus%2C%2095%25%20of%20healthy%20individuals%20have%20body%20temperatures%20between%2096.34F%20and%20100.06F.%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EAnswer%3B%3C%2Fstrong%3E%3C%2Fp%3E%5Btex%5D95%5Ctext%7B%5C%25%7D)
Answer:
1/4
Step-by-step explanation:
To find the roots of the expression, factor the expression by GCF.
The roots are the factors set equal to 0 and solved for x.
2x = 0
x=0
4x-1 = 0
x = 1/4
The sum is the addition of the two roots 0 + 1/4 = 1/4
