The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. ... Because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products.
Answer:
21.2 gm
Explanation:
calculate the mass of butane needed to produce 64.1 g of carbon dioxide to three significant figures and appropriate units
butane is the hydrocarbon C4H10
in combustion, we react hydrocarbons with O2 to form CO2 and H2O
so
C4H10 + O2----------------> CO2 + H2O
BALANCE
2C4H10 + 1302--------> 8CO2 + 10 H2O
the molar mass of CO2 is 12 + 16X2 = 44
64.1 gm of CO2 is
64.1/44 = 1.46 MOLES OF CO2,
FOR EVERY 8 MOLES OF CO2 WE NEED 2 MOLES OF BUTANE IT IS A
8:2 OR 4:1 RATIO. THE MOLES OF C4H10 ARE 1/4 THE MOLES OF CO2
SO
THE MOLES OF C4H10 H10 ARE 1.46/4 =0.365 MOLES
THE MOLAR MASS OF BUTANE IS 58.12
0.365 MOLES OF C4H10 HAS A MASS OF 0.365 X 58.12 = 21.2 gm
C. Ca and Br because they're metals and nonmetals
When the KClO3 decomposes, more oxygen is produced. I don't think I know any other possibility exists.<span />
Answer:
1. micro
2. centi
3. milli
4. kilo
Explanation:
Prefixes, in mathematical exponents, are defined as the alphabetical names associated with the mathematical factors. Some examples are as follows:
10⁶ = Mega
10⁹ = Giga
10⁻⁹ = Nano
10⁻¹² = Pico
So, in order to name the metric system prefixes associated with each of the given mathematical factor, we first convert the factor into exponent form and then write its prefix, as follows:
10⁻⁶ = <u>micro</u>
1/100 = 0.01 = 1 x 10⁻² = <u>centi</u>
0.001 = 1 x 10⁻³ = milli
1000 = 1 x 10³ = <u>kilo</u>
