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3 years ago

Which of these elements would form an ionic bond between them?

Chemistry

2 answers:

Artyom0805 [142]3 years ago

7 0

Answer : The elements form an ionic bond will be, (C) Ca and Br

Explanation:

Ionic bond : It is defined as the bond that is formed by complete transfer of electrons from one atom to another atom.

That means, the atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom.

The ionic bond is usually formed between a metal and a non-metal.

Covalent bond : It is defined as the bond which is formed when sharing of electrons takes place between the atoms.

This is usually formed between two non-metals.

(a) Chlorine and fluorine

In this pair, fluorine is a non-metal and chlorine is also non-metal. So, chlorine and fluorine will form a covalent bond.

(b) Chlorine and chlorine

In this pair, chlorine is a non-metal. So, chlorine and chlorine will form a covalent bond.

(c) Calcium and bromine

In this pair, calcium is a metal and bromine is a non-metal. So, calcium and bromine will form an ionic bond.

(d) Calcium and magnesium

In this pair, calcium and magnesium are metals. So, no bond form between calcium and magnesium.

Hence, the elements form an ionic bond will be, (C) Ca and Br

Pepsi [2]3 years ago

6 0

C. Ca and Br because they're metals and nonmetals

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What weight of sodium hydroxide will react with 73 gram of hydrogen chloride gas at NTP to Produce 117.0 gram of Nacl and 36 gra

Wewaii [24]

Let's write the equation

$\\ \sf\longmapsto {NaOH\atop ?}+{HCl\atop 73g}\longrightarrow {NaCl\atop 117g}+{H_2O\atop 36g}$

According to law of conservation of mass .

Mass of products=Mass of reactants

Let required value be x

$\\ \sf\longmapsto x+73=117+36$

$\\ \sf\longmapsto x+73=153$

$\\ \sf\longmapsto x=153-73$

$\\ \sf\longmapsto x=80g$

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2 years ago

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Consider the reaction given below.

Drupady [299]

Answer:

K = 0.167 s⁻¹

Explanation:

1) Rate law, at a given temperature:

Since all the data are obtained at the same temperature, the equilibrium constant is the same.

Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

r = K [A]ᵃ [B]ᵇ

2) Use the data from the table

Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

Divide r₂ by r₁: [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

Use the first and second set of data to find the exponent a:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

2ᵃ = 2 ⇒ a = 1

3) Write the rate law

r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

4) Use any set of data to find K

With the first set of data

r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K = 0.167 s⁻¹

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