When 1.14 g of octane (molar mass = 114 g/mol) reacts with excess oxygen in a constant volume calorimeter, the temperature of th
e calorimeter increases by 10.0
c?
c?
1 answer:
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<h2>ANSWER OF EACH PART ARE GIVEN BELOW</h2>
Explanation:
A)
We know, each mole contains
atoms.
It is given that mass of one oxygen atom is m= .
Therefore, mass of one mole of oxygen, .
Putting value of n and ,
B)
Given,
Mass of water in glass=0.050 kg = 50 gm.
From above part mass of one mole of oxygen atoms = 16.0 gm.
Therefore, number of mole of oxygen equivalent to 50 gm oxygen
LEARN MORE :
Avogadro's number
Mass perventage of nitrogen in urea, arginine, ornithine is 46.67%, 32.2%,21% respectively.
What is Mass perventage ?
Mass percentage is one way of representing the concentration of an element in a compound or a component in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100.
Molecular mass of urea (NH2CONH2) is= 2× (Atomic mass of N ) + 4 × (Atomic mass of H) + (Atomic mass of C) (Atomic mass of O) = 60
Mass percentage of N =
chemical formula for arginine is C6H14N4O2
molar mass of C6H14N4O2=174g/mol
moles of N atoms in C6H14N4O2=4
mass of N atoms=14*4=56g
mass percent of N in C6H14N4O2=(56/174)*100=32.2%
the chemical formula for ornithine is C5H12N2O2
molar mass of C5H12N2O2=132g/mol
moles of N atoms in C5H12N2O2=2
mass of N atoms in C5H12N2O2=2*14=28
mass percent of N in C5H12N2O2=(28/132)*100=21%
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