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dmitriy555 [2]
3 years ago
13

HELP PLEASE I NEED ALL THE AWNSERS! PLEASEEE

Mathematics
2 answers:
Norma-Jean [14]3 years ago
8 0

Answer:

1) 34

2) 8

3) 8

4) 68

5) 12

6) 4

7) 59

8) 60

9) 25

10) 24

Butoxors [25]3 years ago
7 0

Answer:

1. 34

2. 8

3. 8

4. 68

5. 12

6. 4

7. 41

8. 60

9. 25

10. 24

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5 1/3-3 2/4 find the difference
Vinil7 [7]

Answer:

1 10/12

Step-by-step explanation:

Take the fractions and get them to the same bottom number, 12.  So it would be 5 4/12 -  3 6/12.

Take 1 away from 5 to get 4 and the one you pulled would be 12/12(also equal to 1).  4  16/12 - 3  6/12 would be 1  10/12

8 0
3 years ago
What is the scientific notation for 140000
vampirchik [111]
You move the decimal point forward until it reaches the one so it looks like this:

1.4 x 10⁵ 

the exponent, 5, just tells you how many spaces the decimal point moved.
6 0
3 years ago
company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26
podryga [215]

Answer:

t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435    

p_v =P(t_{(49)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=25.02 represent the sample mean

s=4.83 represent the sample standard deviation

n=50 sample size  

\mu_o =26 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:  

Null hypothesis:\mu \geq 26  

Alternative hypothesis:\mu < 26  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=50-1=49  

Since is a one sided test the p value would be:  

p_v =P(t_{(49)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0
3 years ago
Pls help me on this question
Anna35 [415]

Answer:

C

Step-by-step explanation:

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