Answer: ![P(A\cap B)=\frac{1}{3}](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3D%5Cfrac%7B1%7D%7B3%7D)
![P(A)=\frac{1}{3}](https://tex.z-dn.net/?f=P%28A%29%3D%5Cfrac%7B1%7D%7B3%7D)
![P(B)=1](https://tex.z-dn.net/?f=P%28B%29%3D1)
![P(A|B)=\frac{1}{3}](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
From the given figure it can be seen that
Total number on cube= n(S)=6
Intersection of A and B = n(A ∩ B)= 2
Therefore,
![P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3D%5Cfrac%7Bn%28A%5Ccap%20B%29%7D%7Bn%28s%29%7D%3D%5Cfrac%7B2%7D%7B6%7D%3D%5Cfrac%7B1%7D%7B3%7D)
Also, The number of elements in A = 2
Therefore,
![P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}](https://tex.z-dn.net/?f=P%28A%29%3D%5Cfrac%7Bn%28A%29%7D%7Bn%28s%29%7D%3D%5Cfrac%7B2%7D%7B6%7D%3D%5Cfrac%7B1%7D%7B3%7D)
Similarly, The number of elements in B= 6
Therefore,
![P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1](https://tex.z-dn.net/?f=P%28B%29%3D%5Cfrac%7Bn%28B%29%7D%7Bn%28s%29%7D%3D%5Cfrac%7B6%7D%7B6%7D%3D1)
The formula to find the conditional probability is given by :-
![P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%5Cfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28B%29%7D%5C%5C%5C%5C%5CRightarrow%20P%28A%7CB%29%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B3%7D%7D%7B1%7D%3D%5Cfrac%7B1%7D%7B3%7D)
I’m not sure what you are trying to say in this problem?
Answer:
All payments will be made at the end of the year by using the present value of inflows
Step-by-step explanation:
Present Value Of Inflows = Cash Inflow × Present Value Of Discounting Factor (Rate%,Time Period)
Present Value Of Inflows =
+
+
+ ![60000/1.037^{4}](https://tex.z-dn.net/?f=60000%2F1.037%5E%7B4%7D)
Present Value Of Inflows = 125466.3
Answer:
C
Step-by-step explanation:
related equation
-16t^2 + 32t + 20 = 0
-4t^2 + 8t + 5 = 0
Δ/4 = 16 + 20 = 36
t1 = (-4 + 6)/-4 = -1/2
t2 = (-4 - 6)/-4 = 5/2
-16(t+1/2)(t-5/2)
-16(2t+1/2)(2t-5/2)
-4(2t+1)(2t-5)