Change it into the form
ax^2 + bx + c = 0
x^2 + 13x + 0 = 0
This equation has a common factor, x. Factorise it out.
<h2>x (x + 13) = 0</h2>
K, you have 2 minutes, one minute for one kilometer.
If you're in 60km/h, you're on 1km/m, so, if you cover 1 km in one minute, you need to stay in that speed to get to the train station.
[tex]<span>1\dfrac{1}{7}=\dfrac{1\cdot7+1}{7}=\dfrac{8}{7}\\\\1\dfrac{1}{7}:\dfrac{1}{9}=\dfrac{8}{7}:\dfrac{1}{9}=\dfrac{8}{7}\cdot\dfrac{9}{1}=\dfrac{72}{7}[tex]
Answer: 1 1/7 : 1/9 = 72 : 7
</span>
Answer:
a) x = 18
b) y = 35
c) t = 4.5
Step-by-step explanation:
a) x + x + x = 54
3x = 54
x = 54 ÷ 3
x = 18
b) y/5 = 7
(y/5) × 5 = 7 × 5
y = 35
c) 4t + 6 = 24
4t +6 - 6 = 24 -6
4t = 18
4t ÷ 4 = 18 ÷ 4
t = 4.5
Answer:
(x-3)^2=5=>
(x-3)=±square root of 5
x=+sqr.root5+3 or x=-sqr.root5+3
