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weqwewe [10]
2 years ago
5

HELP HELP PLEASE!!!!!

Mathematics
1 answer:
klio [65]2 years ago
3 0
  1. This problem requires the pathagoriun theorum. The formula is a² + b² = c², which basically means that If you square the two sides that are already labeled, then add them, you will get the length of the side that is unknown.
  2. In this equation, we are given the length of the shortest side, which is 21m. I believe that the length of the side CA is twice the length of the side BC, which would be 42m.
  3. Now you find the square of both, and add them. 21² + 42² (or 441 + 1764) is 2205.
  4. Since the square of 2205 is a decimal, (it is 46.9574275275) you will round it to the nearest whole number, which is 47.

<h2>47</h2>
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A power of 10 with a positive exponent will produce a number that is
Elena-2011 [213]
Example 10 to the 4th power
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3 years ago
Could someone please help me on this
leonid [27]
The dependent variable would be b (affected by the change of n) and the independent variable would be n (affects b). The equation would be
b = 12n.
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3 years ago
In ΔDEF, the measure of ∠F=90°, the measure of ∠D=66°, and EF = 32 feet. Find the length of FD to the nearest tenth of a foot.
Butoxors [25]

Answer:

14.2 ft

Step-by-step explanation:

tan 66° = 32/ FD

FD = 32 / tan 66° = 32 / 2.246 = 14.2

7 0
3 years ago
Find the value of x. x√5=x^4​
Kaylis [27]

Answer:

x=0,\sqrt[6]{5}

Decimal form,

x=0,1.30766048......

Step-by-step explanation:

x\sqrt{5}=x^{4}

x\sqrt{5}-x^{4}=0

(take x as a common factor)

x(\sqrt{5}-x^{3})=0

So,

x=0 and \sqrt{5}-x^{3}=0

for \sqrt{5-x^{3}=0

(add x^{3} for both sides)

\sqrt{5}=x^{3}

x=\sqrt[3]{\sqrt[2]{5} } (multiply 3 by 2)

x=\sqrt[6]{5}

So,

x=0,\sqrt[6]{5}

5 0
2 years ago
It would mean a lot.
LUCKY_DIMON [66]
First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.

Formula to find distance given two points.

Square root (X2 - X1)^2 + (Y2 - Y1)^2

Xa Ya Xb Yb
A = (3, -4) B = (-1, 3)

Xa goes into X2 and Xb goes into X1

(3 - (-1))^2

Ya goes into Y2 and Yb goes into Y1

(-4 - 3)^2

Square root (3 - (-1))^2 + (-4 - 3)^2

Square root (4)^2 + (-7)^2

Square root 16 + 49

Square root 65

= 8.06

The error was Drako had (3 - 4)^2 when it should have been (3 - (-4))^2 because a positive is subtracting a negative.
6 0
2 years ago
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