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stich3 [128]
2 years ago
9

I need help ASAP how do I do this

Mathematics
1 answer:
kicyunya [14]2 years ago
4 0
96. (Text that is longer than 20 characters goes here)
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A model car is 8 inches long and 5.2
Sphinxa [80]
Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.
7 0
3 years ago
Can someone help me :(
k0ka [10]

Answer:

x = 20

Step-by-step explanation:

19 < x < 25

x had to be higher than 19 but lower than 25

18 cant be the answer because it is less than 19

27 cant be the answer because it is higher than 25

that leaves 20, which is the right answer

19 < 20 < 25

4 0
3 years ago
PLS ANSWER !!!! <br><br> what is the formula when finding the slope given in two ordered pairs
Katarina [22]

Answer: Since you already know that the ordered pair is in the format of (x, y), then you can label one of the ordered pairs as 1 and kind of distribute it to get 1(x, y) = (x-sub1, y-sub1). Then just use the slope formula (y2-y1)/(x2-x1).

Step-by-step explanation:

5 0
4 years ago
find the equation of a cubic function whose graph passes through points (3,0) and (1,4) and is tangent to x-axis at the origin
Tomtit [17]

Answer:

y = -2x^2(x - 3)

Step-by-step explanation:

<em><u>Preliminary Remark</u></em>

If a cubic is tangent to the x axis at 0,0

Then the equation must be related to y = a*x^2(x - h)

<em><u>(3,0)</u></em>

If the cubic goes through the point (3,0), then the equation will become

0 = a*3^2(3 - h)

0 = 9a (3 - h)

0 = 27a - 9ah

from which h = 3

<em><u>From the second point, we get</u></em>

4 = ax^2(x - 3)

4 = a(1)^2(1 - 3)

4 = a(-2)

a = 4 / - 2

a = -2

<em><u>Answer</u></em>

y = -2x^2(x - 3)

 

3 0
3 years ago
The graph shows the cost of ice cream. If a teacher wants to buy 20 cones, how much will it cost ?
Volgvan

Answer:

you cannot see the graph. So I cannot answer this question

Step-by-step explanation:

if you add the graph maybe I can help :D

6 0
3 years ago
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