Work in amount of pure acid let x = gallons of pure acid required.
then we have the equation:-
x + 55(0.6) = 0.80(x + 55)
x + 33 = 0.80x + 44
0.20x = 11
x = 11/0.2 = 55 gallons answer
1. 21j-26+4j=21+6-2j
2. 25j-26=27-2j
3. 27j=53
4. j=53/27
hope this helps!!
I’m working on something like that now
x = sqrt{y}k
K is the constant of proportionality.
128 = sqrt{16}k
128 = 4k
128/4 = k
32 = k
x = sqrt{y}k
x = sqrt{36}•32
x = 6 • 32
x = 192
Find y when x = 48.
x = sqrt{y}k
48 = sqrt{y}32
48/32 = sqrt{y}
(48/32)^2 = [sqrt{y}]^2
2.25 = y
