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3 years ago

I need help plzzzzzzzzz

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

You need to create a right triangle and use a^2+b^2=c^2 to find the hypotenuse

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Shelby will take a total of 6 tests. On the first 5 tests, her scores were: 80, 85, 73, 78, 90. If she wants a mean grade of 80,

Andrew [12]

Answer:

Step-by-step explanation:

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3 years ago

Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (6,-5) lies on

Tom [10]

C i guesss because you just said it

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3 years ago

Jesse added two more numbers to his expression, but the sum did not change. What could the two new numbers be? Explain why the n

kenny6666 [7]

Answer:

0 and 0

Step-by-step explanation:

The only number that can be applied to the expression without changing the sum is 0, for example 5 + 10 = 15, adding 2 0's will be 0 + 5 + 10 + 0 = 15 :D

4 0

3 years ago

Read 2 more answers

Determine which function has the greatest rate of change over the interval [0, 2].

ruslelena [56]

Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: $m= \frac{y_{2}-y_{1}}{x_2-x_1}$

Rate of change of $a$ :
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of $a$ :
$m= \frac{y_{2}-y_{1}}{x_2-x_1}$
$m= \frac{4-1}{2-0}$
$m= \frac{3}{2}$
$m=1.5$
The average rate of change of the function $a$ over the interval [0,2] is 1.5

Rate of change of $b$ :
Here the end points are (0,0) and (2,2)
$m= \frac{2-0}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $b$ over the interval [0,2] is 1

Rate of change of $c$ :
Here the end points are (0,-1) and (2,0)
$m= \frac{0-(-1)}{2-0}$
$m= \frac{1}{2}$
$m=0.5$
The average rate of change of the function $c$ over the interval [0,2] is 0.5

Rate of change of $d$ :
Here the end points are (0,0.5) and (2,2.5)
$m= \frac{2.5-0.5}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $d$ over the interval [0,2] is 1

We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>

4 0

3 years ago

Need help with this.

stepan [7]

Third one down. you can tell just by the first two coordinates

6 0

3 years ago