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Hunter-Best [27]
3 years ago
12

Segment ST is a midsegment of triangle XYZ. What is the length of segment XZ?

Mathematics
1 answer:
vekshin13 years ago
5 0

Answer:

B) 2b

Step-by-step explanation:

Segment ST is a midsegment of triangle XYZ, you need to double the length of ST to find the length of XZ

b x 2

2b

If this answer is correct, please make me Brainliest!

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A total of 800 pre-sale tickets and tickets at the gate were sold to football city championship game. If the number of tickets s
Nitella [24]

The number of presale tickets sold is 271

<em><u>Solution:</u></em>

Let "p" be the number of presale tickets sold

Let "g" be the number of tickets sold at gate

<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>

Therefore,

Presale tickets + tickets sold at gate = 800

p + g = 800 ------ eqn 1

<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>

Therefore,

Number of tickets sold at gate = twice the number of pre-sale tickets - 13

g = 2p - 13 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 2 in eqn 1

p + 2p - 13 = 800

3p -13 = 800

3p = 800 + 13

3p = 813

p = 271

Thus 271 presale tickets were sold

4 0
3 years ago
A taxi driver charges an initial fee of $2.00 plus $0.30 per mile. What is the independent variable quantity in this situation?
Effectus [21]

Answer: The .30 per mile is the independent, because it is manipulated, and changed throughout. DRY MIX : Dependent, Responding, Y axis. Manipulated, Independent, X axis.

5 0
3 years ago
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7 0
3 years ago
Match the expressions with their equivalent simplified expressions.
Tasya [4]

Answer:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}


Step-by-step explanation:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}

\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}

\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}

\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}

\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}

\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}

Thus,

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}

3 0
3 years ago
0.032 0.90 0.088 from greatest to least
ioda

Answer:

0.9 , 0.088 , 0.032

Step-by-step explanation:

0.9 --> 1st greatest

0.088 --> 2nd greatest

0.032 --> 3rd greatest

So, 0.9 , 0.088 , 0.032

5 0
2 years ago
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