Answer:
8/125 cu.yd.
Step-by-step explanation:
the answer is simple it is 8/125 cubic yards. the problem gives you the formula and in the picture one side is 2/5yds. so you take that number and plug it into the formula. so you take 2/5 and raise it to the 3rd power giving you the answer of 8/125cu.yd.
Answer:
x = -0.5
Step-by-step explanation:
Here we have the sentence:
"3 to the power 2x+3 is subtracted by 9 which is equal to 2 times 9 to the power x+1 and is subtracted by 6"
The first part:
"3 to the power 2x+3 is subtracted by 9..."
This can be written as:
"... is equal to 2 times 9 to the power x+1 and is subtracted by 6"
Let's solve this for x.
First, we can add 9 in both sides:
We also know the relations:
and
We can write the left part as:
And the right side as:
Then the equation becomes:
Now let's move both terms with 9^x to the left side:
Now remember that:
Ln(a^b) = b*Ln(a)
Then if we apply the Ln( ) function to both sides, we get:
(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
Answer:
1
Step-by-step explanation:
Given,
h ( x ) = - x + 1
To find : h ( 0 ) = ?
h ( 0 )
= - ( 0 ) + 1
= 1
It’s I’m pretty sure 400,000
