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3 years ago

9.2 HW Central Angles, Arc Measures, & Arc Length

Mathematics

1 answer:

kap26 [50]3 years ago

5 0

Answer:

I can help you with this, i just need the actual questions.

Step-by-step explanation:

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Complete the two-column proof by providing a reason for each of the five statements.

Mnenie [13.5K]

Answer:

Step-by-step explanation:

Given:

RUTS is a rectangle.

To prove:

∠USR ≅ ∠SUT

Statements Reasons

1. RUTS is a rectangle 1. Given

2. RU = ST, UT = RS 2. By the definition of a rectangle

3. ∠STU = ∠SRU = 90° 3. Definition of a rectangle

4. ΔURS ≅ ΔSTU 4. By the LL theorem of congruence

5. ∠USR ≅ ∠SUT 5. CPCTC

4 0

2 years ago

Read 2 more answers

Provide a solution for the following equation: 3x + 2y=4

shtirl [24]

Answer:

One solution is to find x and y by doing the following:

Step-by-step explanation:

Let's solve for x.

3x+2y=4

Step 1: Add -2y to both sides.

3x+2y+−2y=4+−2y

3x=−2y+4

Step 2: Divide both sides by 3.

x=-2/3y+4/3

Lets solve for y.

3x+2y=4

Step 1: Add -3x to both sides.

3x+2y+−3x=4+−3x

2y=−3x+4

Step 2: Divide both sides by 2.

y= -3/2x+2

7 0

2 years ago

Find the equation of the line passing through the points (5,21) and (-5,-29)

Assoli18 [71]

Answer:

Look below

Step-by-step explanation:

lets have -29 be y2 and -5 be x2

21 - (-)29

5 - (-)5

Subtracting a negative is just adding it so

21 + 29 50
5 + 5 10

50/10

this simplified, is 5/1 or 5

y=5x+b

now we need to find b, so we substitute y and y

x = 5

y = 21

21=5*5=b

5*5 is 25

now we need to get to 21

25 -4 is 21

b = -4

y=5x-4

3 0

2 years ago

A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

What is 147.3 as a mixed number and what is 147.3 as a improper fraction

mamaluj [8]

147.3 as a mixed nunber is 147 and 3/10, 147.3 as an improper fraction is 1473/10

6 0

3 years ago