we know that Bob can do the whole job in 14 hours, how much of the work has he done in 1 hour only? well since he can do the whole lot in 14 hours in 1 hour he has only done 1/14 th of the job.
we know that James can do it in 18 hours, a bit slower, so in 1 hour he has done only 1/18 th of the job.
let's say it takes both of them working together say "t" hours, so in 1 hour Bob has done (1/14) of the work whilst James has done (1/18) of the work, the whole work being t/t or 1 whole, so for just one hour that'd 1/t done by both Bob and James.
Answer:
C. cos 20/29
Step-by-step explanation:
Cosine is adjacent over hypotenuse, like SohCahToa. Therefore, 20 is the adjacent side and 29 is the hypotenuse (hypotenuse is always the longest side).
Answer: 48÷4 = g
Step-by-step explanation:
Here is the complete question:
Dylan scored a total of 48 points in first 4 games of the basketball season. Which equation can be used to find g, the average number of points he scores per game?
a. 48÷4=g
b. 4÷48=g
c. g÷4=g
d. 4÷g=48
The average number of points Dylan scores per game which has been represented by g will be the total points scored divided by the number of game played. This will be:
g = total point scored ÷ number of games played
g = 48 ÷ 4
Therefore, option A is the right answer.
Answer:
dA/dt = k1(M-A) - k2(A)
Step-by-step explanation:
If M denote the total amount of the subject and A is the amount memorized, the amount that is left to be memorized is (M-A)
Then, we can write the sentence "the rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized" as:
Rate Memorized = k1(M-A)
Where k1 is the constant of proportionality for the rate at which material is memorized.
At the same way, we can write the sentence: "the rate at which material is forgotten is proportional to the amount memorized" as:
Rate forgotten = k2(A)
Where k2 is the constant of proportionality for the rate at which material is forgotten.
Finally, the differential equation for the amount A(t) is equal to:
dA/dt = Rate Memorized - Rate Forgotten
dA/dt = k1(M-A) - k2(A)
