2 years ago

Need help please answer !!!

1 answer:

8 0

I feel like it might be the second one

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Ivahew [28]

$9\cos(2t)=6\implies\cos(2t)=\dfrac23$

Using the fact that cos is 2π-periodic, we have

$\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi$

That is, $\cos(\theta+2n\pi)=\cos\theta$ for any $\theta$ and integer $n$ .

$\implies t=\dfrac12\cos^{-1}\left(\dfrac23\right)+n\pi$

We get 2 solutions in the interval [0, 2π] for $n=0$ and $n=1$ ,

$t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi$

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jek_recluse [69]

B) 43 because they increase 3
c) 32 because they decrease 7

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Monica [59]

Distribute the -2 to get

-16x + 8 < 2x + 5

3 < 18x

1/6 < x

so x > 1/6

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Burka [1]

To study the what ?

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frozen [14]

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