Answer: Enzymes speed up the reaction rate.
Enzymes are regenerated when the reaction is completed.
Enzymes affect the reaction pathway by forming an enzyme-substrate complex.
Explanation:
A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.
The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.
Enzymes are biocatalysts and are highly specific in their action. The specificity of enzymes is due to the presence of some specific regions called as active sites. These active sites form weak bonds with substrate molecules.
The specific binding leads to formation of an enzyme substrate complex which accounts for high specificity of enzyme catalyzed reactions.
Once a proper orientation is achieved, substrate molecules react to form products and products leave the enzyme surface as they do not have any affinity towards the enzyme site and are regenerated at the end.
Enzymes work best in optimum temperature and pH range.The enzyme gets denaturated at high pH and temperature.
Answer:
47.8 moles of H₂O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2H₂ + O₂ —> 2H₂O
From the balanced equation above,
1 mole of O₂ reacted to produce 2 moles of H₂O
Finally, we shall determine the number of mole of water, H₂O, produced by the reaction of 23.9 moles of O₂. This can be obtained as follow:
From the balanced equation above,
1 mole of O₂ reacted to produce 2 moles of H₂O.
Therefore, 23.9 moles of O₂ will react to produce = 23.9 × 2 = 47.8 moles of H₂O.
Thus, 47.8 moles of H₂O were obtained from the reaction.
The equation for the reaction between NaOH and AlCl₃ is as follows;
3NaOH + AlCl₃ ---> 3NaCl + Al(OH)₃
the stoichiometry of NaOH : AlCl₃ is 3:1
3 moles of NaOH reacts with 1 mol of AlCl₃ to produce 1 mol of Al(OH)₃
the number of AlCl₃ moles reacted - 6.5 mol
molar mass of NaOH -(23 +16 +1) = 40 g/mol
the number of NaOH moles reacted = 57.0 g / 40 g/mol
NaOH moles = 1.425 mol
either NaOH or AlCl₃ is in excess and other is the limiting reactant.
limiting reactant is the reactant whose number of moles are fully consumed during the reaction. the reactant that is in excess will have leftover moles that are remaining after the reaction.
If AlCl₃ is the limiting reactant, number of NaOH moles would be thrice the amount of AlCl₃ present,
then number of NaOH moles that should be present - 6.5 * 3 = 19.5 mol
however there are only 1.425 mol of NaOH present, therefore AlCl₃ is in excess.
Then NaOH is the limiting reactant,
the amount of products formed depends on the amount of the limiting reactant present.
stoichiometry of NaOH : Al(OH)₃ is 3:1
the number of Al(OH)₃ moles produced = number of NaOH moles reacted / 3
number of Al(OH)₃ moles are - 1.425 mol /3 = 0.475 mol
molar mass of Al(OH)₃ = (27 +3*16 + 3*1) = 78 g/mol
mass of Al(OH)₃ produced = 78 g/mol * 0.475 mol = 37.05 g
Answer:
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Explanation:
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690 Kelvin is the boiling point of this compound.
Explanation:
Enthalpy is the sum of internal energy and the product of pressure and volume that is how much energy is in the substance.
Entropy is the measurement of randomness and measure of thermal energy per unit of temperature.
ΔH vap of compound is 46.55 kJ⋅ mol− or J.MOL-1
ΔS vap is 67.37 J⋅mol−1⋅K−1.
The boiling point or temperature can be calculated by the formula:
T= 
T =
= 690 Kelvin
The boiling point is the temperature when atmospheric temperature gets equal to
