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goblinko [34]
4 years ago
9

Which of the following statements are true with respect to enzyme activity? Check all that apply. View Available Hint(s) Check a

ll that apply. Enzymes speed up the reaction rate. The activation energy of a reaction increases when an enzyme is used to catalyze the reaction. Enzyme reactivity is not affected by change in pH and temperature. Enzymes are regenerated when the reaction is completed. Enzymes affect the reaction pathway by forming an enzyme-substrate complex.
Chemistry
1 answer:
tiny-mole [99]4 years ago
5 0

Answer: Enzymes speed up the reaction rate.

Enzymes are regenerated when the reaction is completed.

Enzymes affect the reaction pathway by forming an enzyme-substrate complex.

Explanation:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

Enzymes are biocatalysts and are highly specific in their action. The specificity of enzymes is due to the presence of some specific regions called as active sites. These active sites form weak bonds with substrate molecules.  

The specific binding leads to formation of an enzyme substrate complex which accounts for high specificity of enzyme catalyzed reactions.

Once a proper orientation is achieved, substrate molecules react to form products and products leave the enzyme surface as they do not have any affinity towards the enzyme site and are regenerated at the end.

Enzymes work best in optimum temperature and pH range.The enzyme gets denaturated at high pH and temperature.

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At a redox equation, one substance is being oxidized (losing electrons), and the other is being reduced (gaining electrons). In the given reaction:

BrO₃⁻(aq) + Sb³⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq)

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BrO₃⁻(aq) + Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq) + H₂O(l)

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x + 3*(-2) = -1

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3Sb³⁺(aq) → 3Sb⁵⁺(aq) + 6e⁻

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BrO₃⁻(aq) + 3Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + H₂O(l)

Now, we verify the amount of the elements, which must be equal on both sides. So, we multiply H₂O by 3, and H⁺ by 6, and the balanced reaction will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

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