Hi can u help me with this?
2 answers:
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Answer:
a)
b)
c)
Explanation:
Hello,
In this case, in each reaction we must subtract the Gibbs free energy of formation the reactants to the Gibbs free energy of formation of the products considering each species stoichiometric coefficients. In such a way, the Gibbs free energy of formations are:
So we proceed as follows:
a)
b)
c)
Regards.
Answer:
= 64584.7176 g
or
= 64.5847 kg
Explanation:
From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.
We know that from Avogadro's constant,
1 mole of a substance contains 6.02 x 10²³ ions/atoms/units
Thus,
1 mole => 6.02 x 10²³ atoms
x moles=> 6.075 × 10²⁶ atoms
We cross multiply;
x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)
= 1009.1362 moles
1 mole of SO2 = 64 g
1009.1362 moles = ?
=>
= 64584.7176 g
= 64.5847 kg