All categories

2 years ago

Is sodium oxide an acidic oxide or a basic oxide

Chemistry

2 answers:

valkas [14]2 years ago

5 0

Answer:It a Basic oxide

Plz trust Me

Explanation:

HACTEHA [7]2 years ago

3 0

Answer:

Sodium oxide is a simple strongly basic oxide. It is basic because it contains the oxide ion, O2-, which is a very strong base with a high tendency to combine with hydrogen ions. Reaction with water: Sodium oxide reacts exothermically with cold water to produce sodium hydroxide solution.

Explanation:

You might be interested in

Which of the following measurements is expressed to three significant figures? 7.30 × 10–7 km 0.007 m 7077 mg 0.070 mm

Sonbull [250]

7.30 x 10^-7 km. the others have 4 significant figures.

4 0

2 years ago

Ga3+ and Br1- is what formula?

Sladkaya [172]

$\text{GaBr}_3$

8 0

2 years ago

A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$

and,

$\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903$

Now we have to partial pressure of $C_2HBrClF_3$ and $O_2$ .

According to the Raoult's law,

$p^o=X\times p_T$

where,

$p^o$ = partial pressure of gas

$p_T$ = total pressure of gas

$X$ = mole fraction of gas

$p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T$

$p_{C_2HBrClF_3}=0.0971\times 862torr=84torr$

and,

$p_{O_2}=X_{O_2}\times p_T$

$p_{O_2}=0.903\times 862torr=778torr$

Therefore, the partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

6 0

2 years ago

Why are the Flemish called Flemish

Dmitriy789 [7]

Explanation:

The flemish are an ethnic group which belong to the northern part of Belgium called Flanders. They also speak a language called flemish. The major population of Belgium are the flemish. The language they speak is a Low Franconian dialect cluster of the Dutch language.

There was a country called the flanders located in the lowlands of Europe. Any person from this country was considered as flemish previously.

4 0

2 years ago

How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?

valkas [14]

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

C1 = 0.45

V1 = 85

C2= 0.20

V2= ?

0.45 × 85 = 0.20 × V2

V2= (0.45 × 85)/0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

8 0

3 years ago