Answer:
Every oxidation must be accompanied by a reduction.
Explanation:
Oxidation and reduction are complementary processes. There can be no oxidation without reduction and vice versa. It is actually a given an take affair. A specie looses electrons which must be gained by another specie to complete the process. This explains why the selected option is the correct one.
10 electrons
Explanation:
The maximum number of electrons in a single d-subshell is 10 electrons.
The d-sub-orbital used to denote azimuthal or secondary quantum numbers.
The maximum number of electrons in the orbitals of sublevels are:
two electrons in the s-sublevel, it has one orbital
six electrons in the p-sublevel, it has three orbital
ten electrons in the d- sublevel, it has five orbitals
fourteen electrons in the f-sublevel, it has seven orbitals
The maximum number of electrons in an orbital is two.
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Answer:
50 mol
Explanation:
Mass of methane = 800 g
Number of moles of CO₂ produced = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 800 g/ 16 g/mol
Number of moles = 50 mol
Now we will compare the moles of methane and carbon dioxide from balanced chemical equation.
CH₄ : CO₂
1 : 1
50 : 50
Answer:
S + 02= S0 - 4 e- → SIV (oxidation); 2 O0 + 4 e- → 2 O-II (reduction)
C + 02= C
Cu0 + H2SO4= CuO + H2SO4 → CuSO4 + H2O
