Answer:
Number of students in vans =15 and bus =46
Step-by-step explanation:
use variables for the vans and buses
let x= vans and y=buses
Now solve the 2 equations simultaneously
<em><u>remember</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>equations</u></em>
6x+7y=412..........1
6x+9y=504.........2
make x the subject of one equation
and label it equation 3
6x=412—7y

subs 3 into 2





subs 4 into 1





Therefore there are 15 students in each van and 46 students in each bus.
Answer:
or 38
Step-by-step explanation:
If Q is the midpoint of Line PR, then lines PQ and QR add up to equal Line PR. We then get

If you want to know the exact number that PR is, we can do additional steps where PQ = QR.

You would subtract the the amount painted from 500.
500-193=307
They have to paint 307 more.
Answer:
(x,y,z)=( -2, -1 ,5)
Step-by-step explanation:
9x+2y-27z=-155 (1)
-11x-y+37z=208 (2)
19x+6y-52z=-304 (3)
(1) *3 ;(2) *6 ;(3)*1, you have
27x+6y-81z=-465 (1)
-66x-6y+222z=1248 (2)
19z+6y-52z=-304 (3)
(1) +(2), you have
-39x+141z= 783 (4)
(4) /3, you have
-13x +47z=261 (4)
(2) +(3), you have
-47x+170z=944 (5)
From ( 4) and (5), you have equations
-13x +47z=261 (4)
-47x+170z=944 (5)
(4)*(-47); (5)*13, you have
611x-2209z=-12,267 (4)
-611x+2210z=12,272 (5)
(4)+(5), you have
z=5
Replace z=5 in (4), you have
611x- 2209*5=-12,267
611x- 11,045 =-12,267
611x=-1222
x= -2
Replace x=-2, z=5 in (1) , you have
9*(-2) +2y -27*5=-155
-18+2y-135=-155
-18+2y=-20
2y=-2
y=-1
Result (x,y,z)=( -2, -1 ,5)
I don't think there are any equations that passes through (2,2). Please clarify