Answer: X = 3t, Y =2 - t, Z =2
Step-by-step explanation: the plane
x + y + z =4has normal vector
M =<1,1,1> and the line
x = 1 + t, y = 2 − t, z = 2t has direction
v =<1, −1, 2>. So the vector
A= n × v
=<1, 1, 1> × <1, −1, 2>
=<2−(−1),1−2,−1−1>
=<3,−1,−2>
If you evaluate directly this function at x=0, you'll see that you have a zero denominator.
Nevertheless, the only way for a fraction to equal zero is to have a zero numerator, i.e.
![\dfrac{x}{x^3-2x^2+5x}=0\iff x=0](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7Bx%5E3-2x%5E2%2B5x%7D%3D0%5Ciff%20x%3D0)
So, this function can't have zeroes, because the only point that would annihilate the numerator would annihilate the denominator as well.
Moreover, we have
![\displaystyle \lim_{x\to 0} \dfrac{x}{x^3-2x^2+5x} = \lim_{x\to 0} \dfrac{x}{x(x^2-2x+5)} = \lim_{x\to 0} \dfrac{1}{x^2-2x+5} = \dfrac{1}{5}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clim_%7Bx%5Cto%200%7D%20%5Cdfrac%7Bx%7D%7Bx%5E3-2x%5E2%2B5x%7D%20%3D%20%5Clim_%7Bx%5Cto%200%7D%20%5Cdfrac%7Bx%7D%7Bx%28x%5E2-2x%2B5%29%7D%20%3D%20%5Clim_%7Bx%5Cto%200%7D%20%5Cdfrac%7B1%7D%7Bx%5E2-2x%2B5%7D%20%3D%20%5Cdfrac%7B1%7D%7B5%7D)
So, we can't even extend with continuity this function in such a way that ![f(0)=0](https://tex.z-dn.net/?f=f%280%29%3D0)
Answer:
Ok I got it it’s 50
Step-by-step explanation:
because To divide by
1
5
, multiply by its reciprocal, 5.
10÷
1
5
= 105
= 50
Answer:
Step-by-step explanation:
place a marker every mile along the race course. How