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vesna_86 [32]
3 years ago
15

Can someone help me with this?You may answer as much as you can.​

Mathematics
2 answers:
pantera1 [17]3 years ago
8 0

Answer:

17 obtuse triangle

Step-by-step explanation:

hope it helps

dimaraw [331]3 years ago
8 0

Answer:

11. corresponding

12. consecutive interior

13. alternate exterior

14. alternate interior

15. corresponding

16. consecutive interior

17. alternate interior

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Find the value of 58-9x
Yuri [45]
You cannot have an answer to this because it is not an equation
5 0
3 years ago
Somebody please help asap
Elena L [17]

Answer:

B. 4x^2 + \frac{3}{2}x - 7

Step-by-step explanation:

f(x) = \frac{x}{2} - 3

g(x) = 4x^2 + x - 4

(f + g)(x) = f(x) - g(x)

= \frac{x}{2} - 3 + 4x^2 + x - 4

Add like terms

= 4x^2 + \frac{x}{2} + x - 3 - 4

= 4x^2 + \frac{3x}{2} - 7

= 4x^2 + \frac{3}{2}x - 7

6 0
3 years ago
How would you solve this?
musickatia [10]

Answer:

For the equation, you should subtract 2x on both sides to get -y = -2x - 4.  Flip the y's negative sign to get a proper function which is y = 2x + 4.  The y-intercept is at (0, 4) and each unit will move two units up along the x-axis.

3 0
3 years ago
What is the period and amplitude of the function?
nika2105 [10]
The period is 5. Start at x = 0 and trace the curve until you reach the same height as when you were at x = 0 (which is y = 3). The function repeats itself over again once you get to x = 5.

The amplitude is 2.5 since it is half of the vertical distance from the peak y = 3 to the valley y = -2. This distance is 5 units, half of which is 2.5
5 0
3 years ago
A random sample of five Galaxy 8 smartphones is selected from the production line after final assembly, and the result of the we
zepelin [54]
<h2>Answer with explanation:</h2>

Given : A random sample of five Galaxy 8 smartphones is selected from the production line after final assembly, and the result of the weight control measurement is (in grams) are :

X= 155.1, 154.8, 155.5, 155.3, and 154.6.

here, n=5

The average weight :\overline{x}=\dfrac{\sum^{i=5}_{i=1}x_i}{n}

=\dfrac{155.1+154.8+155.5+155.3+154.6}{5}\\\\=\dfrac{775.3}{5}=155.06

∴ Average weight (\overline{x})=155.06 grams

Uncertainty = Standard deviation: \sigma=\sqrt{\dfrac{\sum^{i=5}_{i=1}(x_i-\overline{x})^2}{n}}

=\sqrt{\dfrac{(0.04)^2+(-0.26)^2+(0.44)^2+(0.24)^2+(-0.46)^2}{5}}

=\sqrt{\dfrac{0.532}{5}}=\sqrt{0.1064}=0.326190128606\approx0.33

i.e. Its uncertainty : \sigma=0.33

The fractional uncertainty = \dfrac{\sigma}{\overline{x}}

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7 0
4 years ago
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