Answer:
13. ![\frac{\sqrt[5]{x^4} }{x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B5%5D%7Bx%5E4%7D%20%7D%7Bx%7D)
.
14. 
15. 2.
Step-by-step explanation:
13. 
= 
= 
= 
= 
= 
= 
= .
14. 
.
15. ![\sqrt[3]{2} * \sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D%20%2A%20%5Csqrt%5B3%5D%7B4%7D)
= ![\sqrt[3]{2 * 4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%204%7D)
= ![\sqrt[3]{2 * 2 * 2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%202%20%2A%202%7D)
= ![\sqrt[3]{2 ^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%5E3%7D)
= 2.
Hope this helps!
Most likely: the one that is probably the best
equally likely: two or more are equal in value
certainly: this one is absolute it is the answer
Answer:
120
240
Step-by-step explanation:
We call the length of first part x
Length of second part = y
In the first scenario, it took the tortoise 110 sec to walk the first part and crawl the second.
So,
We have this equation,
x/4 + y/3 = 110
We take the LCM
(3x + 4y)/12 = 110
When we cross multiply
3x + 4y = 110x12
3x + 4y = 1320 ----- equation 1
For scenario 2
x/3 + y/4 = 100
When we take the LCM
(4x + 3y)/12 = 100
We cross multiply
4x + 3y = 100x12
4x + 3y = 1200 ------ equation 2
We now have two equations and we will solve for x and y using simultaneous linear equation.
3x + 4y = 1320 ----- 1
4x + 3y = 1200 ----- 2
We subtract equation 2 from 1 to get
- x + y = 120
We make y subject
y = x + 120 ----- 3
We put the value of y in equation 3 into equation 1
3x + 4(x + 120) = 1320
3x + 4x + 480 = 1320
7x + 480 = 1320
7x = 1320-480
7x = 840
We divide through by 7
x = 840/7
x = 120
We put value of x in equation 3
y = x + 120
y = 120 + 120
y = 240
120 and 240 are the lengths of the 2 parts of the journey.
Thanks
A. -f(1)=1,f(2)=2,f(n)=2f(n-1)f(n-2);n>2
