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Damm [24]
3 years ago
11

Help me on this questions please. ​

Mathematics
1 answer:
Pepsi [2]3 years ago
4 0

Answer:

The formula for exponential growth is f(x)=a(1+r)^x, where a is the initial amount/number, r is the growth rate, and x is the number of years/month/etc. The problem tells us that the initial area is 4500. Every year, it decreases by 7.25%, which is technically -0.0725. "t" is the time. Therefore, we plug in those values into the formula. Then, we have:

f(x) = 4500(1-0.0725)^t

f(x) = 4500(0.9275)^t.

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Given that the measure of ∠x is 73°, and the measure of ∠y is 90°, find the measure of ∠z.
Westkost [7]

Answer:

The measure of z is 17

Step-by-step explanation:

90 plus 73 equals 163

180 minus 163 equals 17

8 0
3 years ago
The ratio of 600m to 3km in simplest form
never [62]
3 km = 3000m
600m:3000m divide by 10
60:300 divide by 10
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2:10 divide 2
*1:5* (simplest form)
6 0
3 years ago
A and B share the cost in a ratio of 3:2. A pays £125 how much does b pay?
german
Hello!
3 + 2 = 5
125 divided by 5 = 25
25 x 3:2 = 2
25 x 2 = 50

5 0
3 years ago
Read 2 more answers
I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
Read 2 more answers
Which of the following ordered pairs could be the y-intercept of a function?
Paul [167]
(-3,2)))))))))))))))))))))))))))))))))))
7 0
3 years ago
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