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Natali5045456 [20]
3 years ago
13

The Wild Dogs and the Rattlers also have membership programs. The Wild Dogs' initial fee is $20 and single game tickets are $1.5

0. The Rattlers' initial fee is $14 and single-game tickets are $2.25. The system of equations for this scenario are y = 1.5x + 20 and y = 2.25x + 14, where x=tickets purchased and y=total cost.
What is the best window range of x-values to find the solution?

x-min=0, x-max=20
x-min=-5, x-max=5
x-min=20, x-max=40
x-min=-20, x-max=0

What is the best window range of y-values to find the solution?

y-min=0, y-max=20
y-min=-5, y-max=5
y-min=20, y-max=40
y-min=-20, y-max=0

What is the solution?

8 games will cost $32
32 games will cost $8
12 games will cost $38
38 games will cost $12
​
Mathematics
1 answer:
tester [92]3 years ago
7 0

Answer:

The first Answer is

 x-min = 0, x-max = 20

What is the best window range of y-values to find the solution?

y-min = 20 , y-max = 40

What is the solution?

8 games will cost $32

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The revenue for a company producing widgets is given by y = -20x2 - 50x + 200, where x is the price in dollars for each widget.
lisov135 [29]

Answer:

The  price is   x =  $2.779

Step-by-step explanation:

From the question we are told that

  The  revenue is  y = - 20x^2  - 50 x + 200

   The cost of production is  y = 30 x - 10

Generally at break even point the cost of production is equal to the  revenue

So

      -20x^2 -50x + 200 =  30x-10

=>   20x^2 +20 -210 = 0

Using the quadratic formula to solve this equation we have that

       x =  $2.779

     

6 0
3 years ago
Read 2 more answers
B<br>8<br>7<br>Find the length of "e" to the<br>nearest tenth using the<br>Pythagorean Theorem.<br>​
weeeeeb [17]

Answer:

≈ 10.63

Step-by-step explanation:

Pythagorean Theorem... Possibly the most easy theory in math once you understood it.

Here's the formula.

AB would be the hypothenuse

BC would be the opposite

CA would be the Adjacent.

But let's not make it complicated though, the question is actually quite easy.

You are asked to find AB, the hypothenuse.

The hypothenuse would be C.

BC and CA would be A and B.

It doesn't matter where are you going to place the numbers.

So,  

= 113

Now we would have to square root 113 since  

is an irrational number, and the question asks you to round ro the nearest tenth.

=10.63014581

≈ 10.63

Your answer would be 10.63

Hope this answer helped :)

5 0
3 years ago
Will give brainliest please help <br><br>-5x+4-x-1​
Serjik [45]

Answer:

− 6 x  +  3

Step-by-step explanation:

hope that helps :)

3 0
2 years ago
In a major hurry to finish this I was stuck doin other homework last year please help me finish this
Irina-Kira [14]

2 = m ≤ −9

3 = p ≥ 5

4  =  x < -10

5 = b < -10

6 = n < 5

7 = n < 6

8 = r ≤ 4

9 = x ≥ 9

10 = p ≤ 0

11 = x < 1

12 = a > 24

6 0
3 years ago
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
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