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Natali5045456 [20]
3 years ago
13

The Wild Dogs and the Rattlers also have membership programs. The Wild Dogs' initial fee is $20 and single game tickets are $1.5

0. The Rattlers' initial fee is $14 and single-game tickets are $2.25. The system of equations for this scenario are y = 1.5x + 20 and y = 2.25x + 14, where x=tickets purchased and y=total cost.
What is the best window range of x-values to find the solution?

x-min=0, x-max=20
x-min=-5, x-max=5
x-min=20, x-max=40
x-min=-20, x-max=0

What is the best window range of y-values to find the solution?

y-min=0, y-max=20
y-min=-5, y-max=5
y-min=20, y-max=40
y-min=-20, y-max=0

What is the solution?

8 games will cost $32
32 games will cost $8
12 games will cost $38
38 games will cost $12
​
Mathematics
1 answer:
tester [92]3 years ago
7 0

Answer:

The first Answer is

 x-min = 0, x-max = 20

What is the best window range of y-values to find the solution?

y-min = 20 , y-max = 40

What is the solution?

8 games will cost $32

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Leokris [45]

Answer:

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4. Markup: $24.75, Retail: $99.74

5. Markup: $48.60, Retail: $97.20

6. Markup: $231.25, Retail: $416.25

Step-by-step explanation:

To get the markup price of an item, multiply it by the markup percentage as a decimal. To get the decimal of a percentage, divide the number by 100. For example, 15% would be 0.15. And then to find how much the item has been marked up by, multiply the current price by the decimal.

$18 * 0.15 = $2.70

So $2.70 is the markup. To find the retail price, you need to add the markup price to the current price given.

$18 + $2.70 = $20.70

So your retail price is $20.70. Repeat these steps for each question to get the answers above.

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3 years ago
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Step-by-step answer:

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Here, we have (horizontal) distance of building to the tower is 400'.

We see two right triangles, each with a leg of 400' (horizontal).

The vertical distances are denoted h1 and h2 for the angles of elevation 24 and 20 degrees respectively.

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h2=400tan20=145.6

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3 years ago
What is the value for f(x)= 3^2x+1 when x =1/2
Papessa [141]
Taking 2x is power of 3.

So it will be like 3^(2*1/2) + 1
You are replacing 'x' with 1/2
and the equation becomes 3^1+1
So, f(1/2) = 4
Answer is 4.

If its like
<span>3^(2x+1)
Then its like 3^[(2*1/2) +1]
It becomes 3^(1+1) = 3^2 = 9
So, the answer is 9
</span>
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3 years ago
5000 for 5 years at 3.6% compounded monthly
Aleksandr [31]
Hello!

The sum at 5 years will be 8600.

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5 0
3 years ago
Individuals filing federal income tax returns prior to March 31 had an average refund of $1102. Consider the population of "last
lions [1.4K]

Answer:

a) The null hypothesis states that the last-minute filers average refund is equal to the early filers refund. The alternative hypothesis states that the last-minute filers average refund is less than the early filers refund.

H_0: \mu=1102\\\\H_a:\mu < 1102

b) P-value = 0.0055

c) The null hypothesis is rejected.

There is enough statistical evidence to support the claim that that the refunds of the individuals that wait until the last five days to file their returns is on average lower than the early filers refund.

d) Critical value tc=-1.96.

As t=-2.55, the null hypothesis is rejected.

Step-by-step explanation:

We have to perform a hypothesis test on the mean.

The claim is that the refunds of the individuals that wait until the last five days to file their returns is on average lower than the early filers refund ($1102).

a) The null hypothesis states that the last-minute filers average refund is equal to the early filers refund. The alternative hypothesis states that the last-minute filers average refund is less than the early filers refund.

H_0: \mu=1102\\\\H_a:\mu < 1102

b) The sample has a size n=600, with a sample refund of $1050 and a standard deviation of $500.

We can calculate the z-statistic as:

t=\dfrac{\bar x-\mu}{s/\sqrt{n}}=\dfrac{1050-1102}{500/\sqrt{600}}=\dfrac{-52}{20.41}=-2.55

The degrees of freedom are df=599

df=n-1=600-1=599

The P-value for this test statistic is:

P-value=P(t

c) Using a significance level α=0.05, the P-value is lower than the significance level, so the effect is significant. The null hypothesis is rejected.

There is enough statistical evidence to support the claim that that the refunds of the individuals that wait until the last five days to file their returns is on average lower than the early filers refund.

d) If the significance level is α=0.025, the critical value for the test statistic is  t=-1.96. If the test statistic is below t=-1.96, then the null hypothesis should be rejected.

This is the case, as the test statistic is t=-2.55 and falls in the rejection region.

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3 years ago
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