Answer:
Second puck travels farther
Step-by-step explanation:
Maximum height of first puck = 3 feet
The height of a second hockey puck is modeled by:


To find maximum height of second puck

Equate the derivative equals to 0
0.15-0.002x=0

75 = x
At x = 75

So, The maximum height of second puck is greater than first puck
So, Second puck travels farther
The triangles are similar because of the SAS postulate. The sides are proportional and angle T is equal in both.
5+4 = 10 - 1
the missing number is 1
Answer:
$6 = cost of small box
$8 = cost of large box
Step-by-step explanation:
Let s = cost of small box
l = cost of large box
(1) 12s + 3l = 96 (2) 6s + 6l = 84
Multiply by -2 <u> -24s - 6l = -192</u>
-18s = - 108
s = $6 = cost of small box
12(6) + 3l = 96
72 + 3l = 96
3l = 24
l = $8 = cost of large box
Answer:g is greater than or equal to 6g + 18/5, or g >_ 6g + 18/5
Step-by-step explanation: 5G- 2 <_ 6g + 16
Add 2 to the 16. 5g <_ 6g + 18.
Divide 5 to both sides. g >_ 6g + 18/5