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Paul [167]
3 years ago
13

How many ways can 12 swimmers make it in first, second and third place

Mathematics
2 answers:
Colt1911 [192]3 years ago
6 0

Answer:1320

Step-by-step explanation:Only one person can win first, second and third place. The total number of placers is 12 times 11 times 10.

den301095 [7]3 years ago
6 0

Answer:

Usig their skills by:

Step-by-step explanation:

Using their strengh, force, move your feet, and arms with strong force to push you ahead faster and faster, if u are really tired I would keep going,

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Sergio ate 3.5 cookies. Each cookie contained 5.7 grams of sugar. How many grams of sugar did Sergio eat?
FrozenT [24]
I’ll get it correct here :)

He ate 19.95 grams of sugar.

3.5 x 5.7 = 19.95
5 0
3 years ago
(04.01)
katrin [286]
The third one, 2 to the power of 5 over 6

√2  * 3√2

convert from radical form to exponent form to solve for the same root
( x^m/n = n√x^m )

2^(1/2) * 2^(1/3)  
2^{3/6} * 2^{2/6} - find common denominator (6)
6√(2^3) * 6√(2^2)  - convert back to radical form 
6√(2^3 * 2^2)- combine

6<span>√(</span>2^5)
then convert to exponential form again
~ 2^5/6 ~

5 0
3 years ago
please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.
likoan [24]

ANSWER:

\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4

STEP-BY-STEP EXPLANATION:

We have the following equation:

f(x)=\sqrt{x}-4

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\  \\ \sqrt{f^{-1}(x)}=x+4 \\  \\ f^{-1}(x)=(x+4)^2 \end{gathered}

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4

4 0
1 year ago
Solve for y<br><br> +5=+5<br><br> Please help!
Amiraneli [1.4K]

Answer:y=10

Step-by-step explanation:

5 0
3 years ago
A scientist removed a sample of 39.1 grams of a chemical from a container. The sample was 5 3/4 grams less than 3/10 of the tota
Oksanka [162]

The first thing we must do for this case is to define variables:

x: the total mass of the chemical in the container

y: a sample of a chemical from a container

We have the following equation:

y = (3/10) x - 5 3/4

Then, for y = 39.1 we have:

39.1 = (3/10) x - 5 3/4

Clearing x:

(3/10) x = 39.1 + 5 3/4

(3/10) x = 44.85

x = (10/3) * (44.85)

x = 149.5 grams

Answer:

the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:

x = 149.5 grams.

3 0
3 years ago
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