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Kruka [31]
2 years ago
7

Write an equation for the perpendicular line to the line whose equation is 4y-5x=20 that contains the point (-2,-3)

Mathematics
1 answer:
yuradex [85]2 years ago
7 0

Answer:

4x + 5y = - 23

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 4y - 5x = 20 into this form

add 5x to both sides

4y = 5x + 20 ( divide all terms by 4 )

y = \frac{5}{4} x + 5 ← in slope-intercept form

with slope m = \frac{5}{4}

given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m}, hence

m_{perpendicular} = - 1 / \frac{5}{4} = - \frac{4}{5}

y = - \frac{4}{5} x + c ← is the partial equation

to find c substitute (- 2, - 3) into the partial equation

- 3 = \frac{8}{5} + c ⇒ c = - \frac{23}{5}

y = - \frac{4}{5} x - \frac{23}{5} ← in slope-intercept form

multiply all terms by 5

5y = - 4x - 23 ( add 4x to both sides )

4x + 5y = - 23 ← in standard form




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Ab and bc form a right angle at point B. if a= (-3,-1) and B= (4,4) what is the equation of BC?
Vesnalui [34]

Answer:

Option C -7x-5y=-48

Step-by-step explanation:

step 1

Find the slope of AB

we have

A(-3,-1) and B(4,4)

The slope m is equal to

m=(4+1)/(4+3)

m=5/7

step 2

Find the slope of BC

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

m1*m2=-1

we have

m1=5/7

substitute

5/7*m2=-1

m2=-7/5

step 3

Find the equation of the line into slope point form

y-y1=m(x-x1)

we have

m=-7/5

B(4,4)

substitute

y-4=-(7/5)(x-4)

Multiply by 5 both sides

5y-20=-7x+28

7x+5y=28+20

7x+5y=48

Multiply by -1 both sides

-7x-5y=-48

3 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE!!!!WILL GIVE BRAINLY TO CORRECT ANSWER!!!!
SSSSS [86.1K]

Answer:

-7 meters

Step-by-step explanation:

-15 after diving down

-15+8 because 8 meters up

-15+8=7

6 0
3 years ago
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