I don’t really know exactly to what degree you need to put in your solution. But I rounded to the nearest tenth degree.
A = 112 degrees
B= 28 degrees (180-112-40 bc all sides of a triangle must equal 180)
C= 40
a= 27.6 (this is the side opposite of angle A)
b= 14 (side opposite b)
c= 19.2 (side opposite c)
HOW TO SOLVE:
c= law of sines, so c/sin(40) = 14/sin(28), multiply both sides by sin(40) so c can be isolated and solved for. c = 14sin(40)/sin(28). Plug into calculator then get answer. c is approximately 19.2.
a = law of sines again, so a/sin(112) = 14/sin(28). Multiply both sides again by sin(112) then solve. a = 14sin(112)/sin(28). Calculator again. a is around 27.6
Answer: 66 degrees
Explanation:
Check out the attached image below. Figure 1 is the original image without any additions or alterations. Then in figure 2, I extend segment BC to form a line going infinitely in both directions. This line crosses segment DE at point F as shown in the second figure.
Note how angles ABC and DFC are alternate interior angles. Because AB is parallel to DE (given by the arrow markers) this means angle DFC is also 24 degrees
Focus on triangle DFC. This is a right triangle. The 90 degree angle is at C.
So we know that the acute angles x and 24 are complementary. They add to 90. Solve for x
x+24 = 90
x+24-24 = 90-24
x = 66
That is why angle CDE is 66 degrees
20 is jenna a ssjsjsn a ans s s s s s s s s s s s. S s s s s s s s. S ss. S s
Answer:
The answer would be 49
Step-by-step explanation:
8(5) + 9
40 + 9
49
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Answer:
red area = 7.74 in^2
Step-by-step explanation:
area of square = 6x6 = 36
radius = 1/2 diameter, radius = 3
area of circle = (3.14)(3^2) = 28.26
36-28.26 = 7.74