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gayaneshka [121]
3 years ago
11

A 75.0 g sample of dinitrogen monoxide is confined in a 3.q L vessel. What is the pressure( in atm) at 115 celsius

Chemistry
1 answer:
Nonamiya [84]3 years ago
7 0
Data Given:
                  Pressure  =  P  =  ?

                  Volume  =  V  =  3.0 L

                  Temperature  =  T  =  115 °C + 273  =  388 K

                  Mass  =  m  =  75.0 g

                  M.mass  =  M  =  44 g/mol

Solution:
              Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
                                      P V  =  n R T
Solving for P,
                                      P  =  n R T / V      ------ (1)
Calculating Moles,
                                      n  =  m / M

                                      n  =  75.0 g / 44 g.mol⁻¹

                                      n  =  1.704 mol

Putting Values in Eq. 1,

                    P  =  (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

                    P  =  18.08 atm
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A chemistry student weighs out 0.154 g of chloroacetic acid (HCH2CICO2) into a 250. mL volumetric flask and dilutes to the mark
erastovalidia [21]

Answer:

11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.

Explanation:

Chloroacetic acid is an monoprotic acid.

Neutralization reaction: ClCH_{2}COOH+NaOH\rightleftharpoons ClCH_{2}COONa+H_{2}O

So, 1 mol of chloroacetic acid is neutralized by 1 mol of NaOH.

Molar mass of chloroacetic acid = 94.5 g/mol

So, 0.154 g of chloroacetic acid = \frac{0.154}{94.5} moles of chloroacetic acid

                                                     = 0.00163 moles of chloroacetic acid

Lets assume V mL of 0.1400 M of NaOH is required to reach equivalence point.

So, number of moles of NaOH needed to reach equivalence point

      = \frac{0.1400\times V}{1000} moles

So, \frac{0.1400\times V}{1000}=0.00163

or, V = 11.6

Hence, 11.6 mL of 0.1400 M of NaOH is required to reach equivalence point.

7 0
4 years ago
How many moles of KF would need to be added to 2500 ml of water to make 1.2 M solution?
Oduvanchick [21]

The number of moles of KF needed to prepare the solution is 3 moles

<h3>What is molarity?</h3>

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of KF </h3>
  • Volume = 2500 mL = 2500 / 1000 = 2.5 L
  • Molarity = 1.2 M
  • Mole of KF =?

Molarity = mole / Volume

1.2 = mole of KF / 2.5

Cross multiply

Mole of KF = 1.2 × 2.5

Mole of KF = 3 moles

Learn more about molarity:

brainly.com/question/9468209

#SPJ1

4 0
2 years ago
What element produces violet light of approximately 412 nm?
Natali [406]
a. Hydrogen

Hydrogen has a line at 410 nm.
Mercury has a line at 405 nm.
Sodium and neon have no lines near 412 nm.
8 0
3 years ago
Read 2 more answers
When pineapple juice disolve in water,it forms like what kind of mixtures.​
Digiron [165]

Explanation:

Pineapple juice often shows an unstable cloud and produces a solid precipitate that is not very attractive for consumers. Cloud stabilization by pectin addition is permitted by EU and Codex standards to counteract this effect. This additive must be labeled and its content should not exceed fixed maximum standards (Website of AIJN Code of Practice). Determination of water-soluble pectins by IFU method 26 (Website of International Fruit and Vegetable Juice Association) can be used for control of this parameter. Pectin addition to pineapple juice or juice concentrate, etc. may also be detected after its isolation by 13C isotopic analysis (Hammond, 2006) as explained later.

5 0
2 years ago
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In a study of the following reaction at 1200 K it was observed that when the equilibrium partial pressure of water vapor is 15.0
sp2606 [1]

Answer:

The value of K_p for this reaction at 1200 K is 4.066.

Explanation:

Partial pressure of water vapor at equilibrium = p^o_{H_2O}=15.0 Torr

Partial pressure of hydrogen gas at equilibrium = p^o_{H_2}=?

Total pressure of the system at equilibrium P = 36.3 Torr

Applying Dalton's law of partial pressure to determine the partial pressure of hydrogen gas at equilibrium:

P=p^o_{H_2O}+p^o_{H_2}

p^o_{H_2}=P-p^o_{H_2O}=36.3 Torr- 15.0 Torr = 21.3 Torr

3 Fe(s) 4 H_2O(g)\rightleftharpoons Fe_3O_4(s) 4 H_2(g)

The expression of K_p is given by:

K_p=\frac{(p^o_{H_2})^4}{(p^o_{H_2O})^4}

K_p=\frac{(21.3 Torr)^4}{(15.0 Torr)^4}=4.066

The value of K_p for this reaction at 1200 K is 4.066.

6 0
3 years ago
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