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The grams of solute are required.
The mass of solute is 3.5 g
c = Molarity = 0.1 M
M = Molar mass = 350 g/mol
V = Volume of solution = 100 mL = 0.1 L
n = Number of moles
m = Mass of solute
Molarity is given by
Molar mass is given by
The mass of solute is 3.5 g
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Answer:
R aluminium = 2.63x10^-6 Ω*cm
Rcopper = 1.7 x10^-6 Ω*cm
I would use Cu as interconnections in advanced CMOS nodes.
Explanation:
the conductivity formula equals:
σ = n*g*u
n = carrier concentration
u = mobility
g = charge of carrier
The resistivity is equal to:
R = 1/σ
For the aluminium, we have:
g = 1.602x10^-19 C
R = 1/(1.98x10^23 * 1.602x10^-19 * 12 = 2.63x10^-6 Ω*cm
For copper:
R = 1/(8.5x10^22 * 1.602x10^-19 * 43.2) = 1.7 x10^-6 Ω*cm
According to the calculations found for both resistivities, I would use Cu as interconnections in advanced CMOS nodes, since copper has a lower resistivity and therefore, copper conducts electricity better.
The balanced chemical equation for the reaction is
<h3>6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g) </h3>
From the question given above, we were told that:
solid cesium reacts with solid cesium nitrite to form solid cesium oxide and nitrogen gas.
The equation for the reaction can be written as follow:
Caesium => Cs
Caesium nitrite => CsNO₂
cesium oxide => Cs₂O
nitrogen gas => N₂
Caesium + Caesium nitrite —> Caesium oxide + Nitrogen gas
<h3>Cs + CsNO₂ —> Cs₂O + N₂</h3>
The above equation can be balance as follow:
Cs + CsNO₂ —> Cs₂O + N₂
There are 2 atoms of N on the right side and 1 atom on the left side. It can be balance by writing 2 before CsNO₂ as shown below:
Cs + 2CsNO₂ —> Cs₂O + N₂
There are 2 atoms of Cs on the right side and a total 3 atoms on the left side. It can be balance by writing 6 before Cs and 4 before Cs₂O as shown below:
6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) + N₂(g)
Now the equation is balanced
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Sr will always have 38 protons because that is its atomic number. Normally Sr has 38 protons and 49 neutrons yielding an atomic mass of 87. unless you are dealing with an isotope of Strontium in which 3 additional neutrons would give you the 53 neutrons in your answer, (38p, 52n).
