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2 years ago

What is the name for a star that has two shells of hydrogen and helium undergoing fusion?

Chemistry

1 answer:

nasty-shy [4]2 years ago

6 0

Answer:

I am not so sure but I think it is A.

Explanation:

If i got it wrong sorry.... :(

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3 years ago

What will i observe when i bring the elrctro magnet near to some aluminum clips?

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3 years ago

Calculate the molarity of a solution prepared by dissolving 5.850g of solid NaCl in enough water to make 200mL of the solution?

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6 0

3 years ago

someone pls help me with my chemistry test plsss my teacher changes the questions so I can't search them up. its 21 questions so

shusha [124]

Answer:

Correct option is

5 liters of CH

(g)NO

at STP

No. of molecules=

22.4

mol=

22.4

×N

molecules

A) 5ℊ of H

(g)

No. of moles=

mol=

×N

molecules

B) 5l of CH

(g)

No. of moles of CH

22.4

mol=

22.4

molecules

C) 5 mol of O

=5N

molecules

D) 5×10

molecules of CO

(g)

Molecules of 5l NO

(g) at STP=5l of CH

(g) molecules at STP

Therefore, option B is correct.

7 0

2 years ago

If the percent yield for the following reaction is 75.0%, and 25.0 g of NO₂ are consumed in the reaction, how many grams of nitr

victus00 [196]

Answer:

17.1195 grams of nitric acid are produced.

Explanation:

$3NO_2+H_2O\rightarrow 2HNO_3+NO$

Moles of nitrogen dioxide :

$\frac{25.0 g}{56 g/mol}=0.5434 mol$

According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.

Then 0.5434 moles of nitrogen dioxides will give:

$\frac{2}{3}\times 0.5434 mol=0.3623 mol$ of nitric acid.

Mass of 0.3623 moles of nitric acid :

$0.3623 mol\times 63 g/mol=22.8260 g$

Theoretical yield = 22.8260 g

Experimental yield = ?

$\%Yield=\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100$

$75\%=\frac{\text{Experimental yield}}{22.8260 g}$

Experimental yield of nitric acid = 17.1195 g

7 0

3 years ago