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suter [353]
3 years ago
14

Alexander is going to an amusement park. The price of admission into the park is $15, and once he is inside the park, he will ha

ve to pay $3 for every ride he rides on. How much money would Alexander have to pay in total if he goes on 5 rides? How much would he have to pay if he goes on rr rides?
Mathematics
1 answer:
lukranit [14]3 years ago
3 0

Given :

Admission price , A = $15 .

Price of each ride , p = $3 .

Number of rides , r = 3 .

To Find :

Total money spend if he goes on 5 rides and for r number of rides .

Solution :

Let , total amount paid is P .

First we find the general equation :

Total \ amount = Admission\ Fee - r\times ( Fee\ per\ ride )

P=15+3r

Now , for r = 5 , total price is :

P=15+3\times 5\\\\P=15+15=\$30

Hence , this is the required solution .

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Patrick is keeping track of how far he jogs each morning.
katrin2010 [14]

Answer:

21:50

Step-by-step explanation:

We need to find the ratio of 420 m to 1 km.

We know that,

1 km = 1000 m

So,

The ratio becomes,

\dfrac{420\ m}{1\ km}=\dfrac{420\ m}{1000\ m}\\\\=\dfrac{42\ m}{100\ m}\\\\=\dfrac{21}{50}

So, the required ratio is 21:50.

5 0
3 years ago
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
2 years ago
Please I will give 5 points
andrew11 [14]

Answer:B

Step-by-step explanation:

5 0
2 years ago
Trigonometry (ASAP) (Urgent) ​
Olin [163]

Answer:

h = 1.403733341286

Step-by-step explanation:

17.

the triangle of sides ‘l’ and ‘l-h’ is a right angled triangle.

Then

\cos \theta =\frac{l-h}{l}

Then

l\cos \theta =l-h

Then

h=l-l\cos \theta

18.

For l = 6  and  θ = 40 :

h=l-l\cos \theta

  = 6-6cos(40)

  = 1.403733341286

8 0
1 year ago
Need help asap!!!!!!!!!!!!!!!!!
ValentinkaMS [17]

Answer:

Step-by-step explanation:zd mvx c,mkjbklb xblkj bh

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