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solmaris [256]
3 years ago
14

determine whether the point 1,5 is a solution to the system of inequalities below y>3x , y>/2x+1

Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0
Determine whether the point 1,5 is a solution to the system of inequalities below y>3x , y>/2x+1

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2 &lt; X &lt; 8<br> x is an integer.<br> Write down the possible values of x.
Rufina [12.5K]

answer: 3, 4, 5, 6, 7

4 0
3 years ago
You guys are life savers but does anyone know the answers to these questions? I’m so confused rn
timofeeve [1]

Answer:

The third choice

Step-by-step explanation:

We need to find the slope and y-intercept of the line and then put it into y = mx = b form. To find the slope, pick a point on the line; I will use (-2, 5); count how many units up you need to go to get to the next point on the line, which in this case it would be 3. The count how many to the right or left you would need to go, which is 1 to the left. Moving left means a negative, so it is -1. Your slope fraction would be \frac{3}{-1} , since slope is rise over run. You can sub this fraction in for m in y = mx + b, which will give you a revised equation of y = -3x = b. To find the y intercept, or b, just find the point where the line crosses the y-axis, which is -1. So, the equation is now y = -3x - 1.The correct answer is third choice.

6 0
3 years ago
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
Read 2 more answers
The cost of a lack has increased by 30% to £65. Work out the original price
Sveta_85 [38]
Cost of lack increased by 30%

new cost of lack will be = 100% + 30% = 130%

We are given that new cost = £65

Thus 130% of original cost = 65

100% of original cost = 65 × 100/130 = £50

Thus original price was £50
7 0
3 years ago
A cylinder is filled with 900 liters of water.find the area of its base if height of cylinder is 20dm.
Lisa [10]
The formula of the volume of a cylinder:

V=\pi r^2H\\\\where:\\\\r-a\ radius\\H-a\ height\\\pi r^2-an\ area\ of\ base

We have:

V=900\ liters\\1L=1dm^3\ therefore\ V=900L=900dm^3

and

H=20\ dm

substitute:

\pi r^2\cdot20=900\ \ \ |:20\\\\\pi r^2=45\ dm^2

Answer: The area of a base of the cylinder is equal 45 dm².
5 0
3 years ago
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