1. y=3/4x-3 (just from a triangle from one point on the line to anotheron the line where both end at a point.
2. y=5/1x which is also y=5x (basically subtract y^2-y^1/ x^2-x^1 ex. -2--7/5-4
3.y=2/3x-1/2
4.-3/-1 which is two negatives dividing which makes it positive. y=3x
5.cant see
6. Find slope first. y=3x then use point (1,1) move one left and 3 down. and the y intercept would be -2
Step-by-step explanation:
15) 13x = 130 x = 10
16) 16x+2+43x+1 = 180 59 x = 177 x = 3
17) 29x+3+31x-3 = 180 60x = 180 x = 3
18) 16x -5 + -5 + 22x = 180 38x = 190 x = 5
Hello mate ☺️,
We know that m < 2 = 96°, as,
(Alternate angles are equal)
Now we know that m < 5 = 96°, so,
(Linear Pair angles are supplementary)
![→ 96° + m < 8 = 180°](https://tex.z-dn.net/?f=%E2%86%92%2096%C2%B0%20%2B%20m%20%3C%208%20%3D%20180%C2%B0)
![→ m < 8 = (180 - 96)°](https://tex.z-dn.net/?f=%E2%86%92%20m%20%3C%208%20%3D%20%28180%20-%2096%29%C2%B0)
![→ m < 8 = 84°](https://tex.z-dn.net/?f=%E2%86%92%20m%20%3C%208%20%3D%2084%C2%B0)
Therefore, <u>m<5 = 96°</u> & <u>m<8=84°</u>
✍️ <em>By </em><em>Benjemin</em> ☺️