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2 years ago

Please help transition math question

Mathematics

1 answer:

marissa [1.9K]2 years ago

4 0

The answer is the third option which is AEF and FED, AEG and CEG

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Mr. Chavez needs 7 lbs of gummy bears to make gummy bears with chamoy

Svetradugi [14.3K]

Answer:

3 lbs

Step-by-step explanation:

7 lbs total

2 + 2 = 4 so we already have 4lbs

7 - 4 = 3

we need 3 more lbs

8 0

2 years ago

If a system of linear equations has no solution, what do you know about the slopes and y-intercepts of the graphs of the equatio

daser333 [38]

No solution means the slopes of the equations are the same, because they're parallel. Because they different and parallel lines, the y-intercepts will be different.

6 0

3 years ago

Please help me for this question

Nezavi [6.7K]

Answer:

Mid-point: $(0,-5)$

Equation: $y=\frac{7}{3}x-5$

Step-by-step explanation:

To find the mid-point of AB, simply add up their x and y coordinates and divide by 2 respectively to find their middle point.

$(\frac{{x__A}+{x__B}}{2},\frac{{y__A}+{y__B}}{2})$

$(\frac{{-7}+{7}}{2},\frac{{-2}+{(-8)}}{2})$

$(0,-5)$

To find the perpendicular slope that passes through the mid-point, we need to know the slope between AB first.

Slope of AB: $\frac{{y__2}-{y__1}}{{x__2}-{x__1}}$ = $\frac{{-8}-{-2)}}{{7}-{(-7)}}$ = $\frac{-6}{14}$ = $\frac{-3}{7}$

Multiplying slopes that are perpendicular with each other always results in -1.

$\frac{-3}{7}*m = -1$

$m=\frac{7}{3}$

By the point slope form:

$({y}-{y__1})=m({x}-{x__1})$

Plug in the coordinates of the mid-point:

$({y}-{(-5)})=\frac{7}{3} ({x}-{0})$

Equation: $y=\frac{7}{3}x-5$

6 0

2 years ago

Does the equation y= 4x - 9 show a proportional relationship between x and y

andrew-mc [135]

Yes

Mark brainliest please

7 0

2 years ago

Math am I right, well i need this asap. thanks for all the help!

monitta

Answer:

Step-by-step explanation:

5 0

2 years ago