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kotykmax [81]
2 years ago
15

1. A, D, E 2. A, B, D 3. C, D, E 4. A, B, C

Mathematics
1 answer:
RUDIKE [14]2 years ago
8 0

Answer:

4. A,B,C because the dotted line on A B C have the same shape

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If c=3 what is the answer for c to the third power/2
erik [133]

Answer:

9

Step-by-step explanation:

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HELP ME PLEASE!! LOTS OF POINTS
WARRIOR [948]

Answer:

all rational

Step-by-step explanation:

find the square root then add to fraction

down below is a cheatsheet.

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2 years ago
Warm up<br> 1) Change 8/15 to a decimal.
Alecsey [184]

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5.333...

Step-by-step explanation:

You devide 8 by 15 and get the decimal form of this fraction.

It is 5.3 repeating

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the area of a mirror is 225 square inches and its width is 13 3/4 inches. Will the mirror fit in a space that is 15 inches by 16
Tems11 [23]
A = 225 in^2
W = 13.75

15x16 = 240 in^2

240/13.75 = 17.45 in

the mirror would not fit in a space that is 15 by 16 inches since its approximately 13 by 17 inches
6 0
3 years ago
A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a lon
algol [13]

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis:\mu_{men} \leq \mu_{women}

Alternative hypothesis:\mu_{men} > \mu_{women}

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is z_{calc}

Since is a right tailed test test the p value would be:

p_v =P(Z>z_{calc})=0.225

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that p_v >\alpha

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

8 0
3 years ago
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