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3 years ago

The ratio of the measures of the angles of a triangle is 3:4:8 what are the measures of the angles?

Mathematics

1 answer:

evablogger [386]3 years ago

5 0

Answer:

36 and 48 and 96

Step-by-step explanation:

add 3+4+8=15

all of the angles in a triangle have to add up to 180

so 180÷15=12

now for this ratio, each part will equal 12

so we have to multiply each of the parts by 12

3×12=36

4×12=48

8×12=96

those are the measures of the angles

you can add them up again and see that they equal 180

you can try dividing and you will see that they also equal the ratio

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jok3333 [9.3K]

$x = \sqrt{ { \sqrt{18} }^{2} + {2}^{2} } = \sqrt{18 + 4} = \sqrt{22} \\ y = \sqrt{ { \sqrt{18} }^{2} + {9}^{2} } = \sqrt{18 + 81} = \sqrt{99} = 3\sqrt{11}$

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3 years ago

Antonio runs 4 miles each day. How

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3 years ago

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What is the value of x? 3x−8=8x+4/2 Enter your answer in the box

krek1111 [17]

For this case we must find the value of "x" of the following expression:

$3x-8 = \frac {8x + 4} {2}$

Multiplying by 2 on both sides of the equation:

$2 (3x-8) = 8x + 4\\6x-16 = 8x + 4$

Subtracting 8x from both sides of the equation:

$6x-8x-16 = 4\\-2x-16 = 4$

Adding 16 to both sides:

$-2x = 4 + 16\\-2x = 20$

Dividing between -2 on both sides:

$x = \frac {20} {- 2}\\x = -10$

Answer:

$x = -10$

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3 years ago

Read 2 more answers

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

3 years ago

In a right triangle, if sin 0 = 8/17 what is cos 0 explain?

Oliga [24]

Answer:

We have sin² x + cos² x =1 for all real x.

Therefore, sin² x = 1 – cos² x = 1 – (8/17)² = 1 – 64/289 = 225/289 = (15/17)².

However, remember that if x² = a², then x can be +a or –a.

Therefore, sin x can be either –15/17 or +15/17.

Everyone but Anirban so far has forgotten the negative solution.

Step-by-step explanation:

Given that sinθ=817 and cosθ<0 , we have: cosθ=−√1−sin2θ. cosθ=−√1−(817)2. cosθ=−√1−64289.

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2 years ago