There are two types of succession that lead to the increasment of the ecosystem:
1. Primary succession is the change in the structure of an ecosystem represented with the increase of the ecological community on an area that has not been previously occupied by an ecological community such as area after the lava flow or glacial lake. The first organisms of primary succession are pioneer plants usually, lichens and mosses.
2. Secondary succession includes the step of removal of pre-existing community and after that, colonization of the new one.
<span>Stamen produces pollen so the best answer is stamen.
I hope it helped :)</span>
Answer:
Trichomoniasis
Explanation:
Trichomoniasis is an sexually transmitted disease that affects around 30% of world population. The common symptoms are frequent urge to urinate, vaginal bleeding, burning sensation during urination.
The causative agent of trichomoniasis is a protozoa called <em>Trichomonas vaginalis</em>. This protozoan can be transfer through the genital contact. The protozoa can easily be transfer from affected individual to the healthy individual.
Thus, the correct answer is option (3).
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
