Question

If the solubility of a gas is 7.5 g/L at 404 kPa pressure, what is the solubility of the gas when the pressure is 202 kPa? Show your work.

Answer 1

Data:

C1 (initial concentration) = 7.5 g/L
P1 (initial pressure) = 404 kPa
C2 (final concentration) = ? (g/L)
P2 (final pressure) = 202 kPa

We apply the data to the formula of the solubility of gases in a liquid (Henry's Law), let us see:

$\boxed{ \dfrac{C_1}{P_1} = \dfrac{C_2}{P_2}}$

Solving:

$\dfrac{7.5}{404} = \dfrac{C_2}{202}$

$404*C_2 = 7.5*202$

$404C_2 = 1515$

$C_2 = \dfrac{1515}{404}$

$\boxed{\boxed{C_2 = 3,75\:g/L}}\end{array}}\qquad\checkmark$

I hope this helps. =)