30s-18 is the answer jus add all the sides together/ add the like terms then solve it
t=D/r
Divide r by both sides to get t by itself.
Answer:
Tom’s age is 7 years
Mary’s age is 13 years
Step-by-step explanation:
Since we do not know the ages, let’s represent the ages by variables at first.
Let m represent mary’s age will t represent Tom’s age.
Now, let’s proceed to have equations.
Adding square of Tom’s age (t^2) to mary’s age give 62
t^2 + m = 62 •••••••(i)
Adding square of mary’s age (m^2) to Tom’s age give 176
m^2 + t = 176 •••••••(ii)
Now, to get the individual ages, we will need to solve both equations simultaneously.
Solving both equations simultaneously without mathematical softwares can be a little hard.
By the use of mathematical software ( wolfram alpha to be specific), we can input both equations and allow the software to solve.
By inputing these equations, we have the values of t to be 7 and m to be 13
And if we try to check by inspection, we can see that these values are actually correct.
7^2 + 13 = 62
13^2 + 7 = 176
Answer:
Perimeter: 2(x+3) + 2(x+2)
Step-by-step explanation:
Answer:
(x + 1)² = 7
Step-by-step explanation:
Given:
-2x = x² - 6
We'll start by rearranging it to solve for zero:
x² + 2x - 6 = 0
The first term is already a perfect square so that's fine. Normally, if that term had a non-square coefficient, you would need to multiply all terms a value that would change that constant to a perfect square.
Because it's already square (1), we can simply move to the next step, separating the -6 into a value that can be doubled to give us the 2, the coefficient of the second term. That value will of course be 1, giving us:
x² + 2x + 1 - 1 - 6 = 0
Now can group our perfect square on the left and our constants on the right:
x² + 2x + 1 - 7= 0
x² + 2x + 1 = 7
(x + 1)² = 7
To check our answer, we can solve for x:
x + 1 = ± √7
x = -1 ± √7
x ≈ 1.65, -3.65
Let's try one of those in the original equation:
-2x = x² - 6
-2(1.65) = 1.65² - 6
- 3.3 = 2.72 - 6
-3.3 = -3.28
Good. Given our rounding that difference of 2/100 is acceptable, so the answer is correct.
